Math Problem Statement

Write the prime-power factorization of each.

Solution

I can help you with the prime-power factorization of each number on the sheet. Let’s go through each problem one by one:

  1. 48:
    48=24×3148 = 2^4 \times 3^1

  2. 35:
    35=51×7135 = 5^1 \times 7^1

  3. 46:
    46=21×23146 = 2^1 \times 23^1

  4. 40:
    40=23×5140 = 2^3 \times 5^1

  5. 66:
    66=21×31×11166 = 2^1 \times 3^1 \times 11^1

  6. 100:
    100=22×52100 = 2^2 \times 5^2

  7. 75:
    75=31×5275 = 3^1 \times 5^2

  8. 72:
    72=23×3272 = 2^3 \times 3^2

  9. 65:
    65=51×13165 = 5^1 \times 13^1

  10. 81:
    81=3481 = 3^4

  11. 80:
    80=24×5180 = 2^4 \times 5^1

  12. 54:
    54=21×3354 = 2^1 \times 3^3

  13. 972:
    972=22×35972 = 2^2 \times 3^5

  14. 660:
    660=22×31×51×111660 = 2^2 \times 3^1 \times 5^1 \times 11^1

Would you like more details on how any of these factorizations were found, or do you have any further questions?

Here are 5 relative questions:

  1. How can prime-power factorizations help simplify mathematical expressions?
  2. What is the prime-power factorization of 144?
  3. How do you find the greatest common divisor (GCD) using prime factorization?
  4. What is the prime-power factorization of 90?
  5. How can prime factorization be used to solve least common multiple (LCM) problems?

Tip: When breaking a number down into primes, always start by dividing by the smallest prime number (2), then work your way up!

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Math Problem Analysis

Mathematical Concepts

Prime factorization

Formulas

Prime-power factorization: n = p1^e1 * p2^e2 * ... * pk^ek

Theorems

Fundamental Theorem of Arithmetic

Suitable Grade Level

Grades 6-8