Math Problem Statement

The data follows a trend of the form y = ax^n, where a and n are constants. Complete the table of log values, plot log y against log x, and estimate a and n.

Solution

Part b: Analysis of the Plot

The graph shows the relationship between logy\log y and logx\log x, with the red line representing the line of best fit. This linear relationship suggests that the data follows a power law, consistent with the equation y=axny = ax^n, as stated in the question.

Part c: Estimating aa and nn

The equation of the line of best fit from the log\log-log\log plot is of the form: logy=loga+nlogx\log y = \log a + n \log x From this, we can extract the slope nn and intercept loga\log a by fitting the line.

I will now calculate the slope nn and intercept loga\log a from the linear regression model.From the linear regression model:

  • The slope n1.40n \approx 1.40
  • The intercept loga0.54\log a \approx 0.54, which means a3.46a \approx 3.46

Thus, the estimated values are:

  • a3.5a \approx 3.5
  • n1.4n \approx 1.4

These values correspond to the equation y=axny = ax^n, with y=3.5x1.4y = 3.5x^{1.4}.


Would you like more details or have any questions?

Here are 5 related questions to expand your understanding:

  1. How would the line change if the data followed a different power law, say y=ax2y = ax^{2}?
  2. Why is it useful to take the logarithm of both xx and yy in this type of analysis?
  3. What does the value of nn represent in terms of the relationship between xx and yy?
  4. How can you confirm the accuracy of the estimated aa and nn values using the original data?
  5. How would you interpret negative values of nn in the equation y=axny = ax^n?

Tip: When dealing with power laws, plotting logarithms often transforms non-linear relationships into straight lines, making it easier to estimate parameters like aa and nn.

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Math Problem Analysis

Mathematical Concepts

Logarithmic transformation
Linear regression
Power law

Formulas

y = ax^n
log y = log a + n log x

Theorems

Power law
Linear equation in logarithmic scale

Suitable Grade Level

Grades 10-12