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The circuit shown is a combination of series and parallel components with three batteries (each 1.5 V), making a total of 4.5 V across the entire circuit. We are asked to find the potential difference across Lamp 2, which is positioned in a parallel branch of the circuit.

### Analysis:
1. The three batteries provide a total voltage of \( 1.5 \, V + 1.5 \, V + 1.5 \, V = 4.5 \, V \).
2. Lamp 2 is in parallel with Lamp 1. In a parallel circuit, the voltage across each branch is the same as the total voltage across the parallel branches.
3. Since the total voltage supplied by the batteries is 4.5 V and this voltage is across both lamps, the voltage (or potential difference) across Lamp 2 is the same as the battery voltage.

### Conclusion:
The potential difference across Lamp 2 is **4.5 V**.

Would you like more details or have any questions?

Here are 5 relative questions you might be interested in:
1. What happens to the current in parallel vs. series circuits?
2. How does adding more resistors in parallel affect the total resistance?
3. Why is the voltage the same across components in a parallel circuit?
4. How does the total voltage in a series circuit relate to individual cell voltages?
5. What is the significance of Kirchhoff's Voltage Law in circuits like this?

**Tip**: In parallel circuits, the voltage across each branch remains the same, regardless of the resistance in each branch!

What is the potential difference across lamp 2 in the given circuit?

Learn how to calculate the potential difference across a lamp in a parallel circuit using Kirchhoff's Voltage Law and Ohm's Law. This problem explores key concepts in electrical circuits and is suitable for high school students (Grades 9-12).

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