To determine the possible subsets of the set \(\{0, 1, 2\}\), we can follow the rule that the number of subsets of a set with \(n\) elements is given by \(2^n\).

In this case, the set \(\{0, 1, 2\}\) has 3 elements, so the number of possible subsets is:
\[
2^3 = 8
\]

Here are the 8 possible subsets of \(\{0, 1, 2\}\):

1. \(\emptyset\) (the empty set)
2. \(\{0\}\)
3. \(\{1\}\)
4. \(\{2\}\)
5. \(\{0, 1\}\)
6. \(\{0, 2\}\)
7. \(\{1, 2\}\)
8. \(\{0, 1, 2\}\)

These are all the subsets, including the empty set and the set itself.

Would you like more details or clarification on how subsets work?

Here are 5 related questions to explore further:
1. How many subsets does a set with 5 elements have?
2. What is the difference between a subset and a proper subset?
3. How do you determine the number of proper subsets of a set?
4. What is a power set, and how is it related to subsets?
5. Can subsets contain repeated elements?

**Tip:** The empty set \(\emptyset\) is always a subset of any set, no matter its size.

Discover all possible subsets of the set {0, 1, 2}. This problem explores set theory concepts, including subsets and power sets, with a total of 8 possible subsets calculated using the formula 2^n. Suitable for students in Grades 6-8.

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