Math Problem Statement

The polynomial function f is given by f(x) = ax^b, where a is an integer and b is a positive integer. It is known that lim_{x → ∞} f(x) = −∞ and lim_{x → −∞} f(x) = −∞. Which of the following statements must be true?

Solution

Let's analyze the question step-by-step.

Problem Overview:

The polynomial function is given as f(x)=axbf(x) = ax^b, where:

  • aa is an integer.
  • bb is a positive integer.

It is stated that: limxf(x)=andlimxf(x)=.\lim_{x \to \infty} f(x) = -\infty \quad \text{and} \quad \lim_{x \to -\infty} f(x) = -\infty.

We need to determine which of the statements provided (A, B, C, D) must be true based on the behavior of the function.


Key Observations:

  1. Polynomial Degree (Exponent bb) Behavior:

    • If bb is even, xbx^b will have the same sign for both positive and negative xx, because: (x)b=xb(even power).(-x)^b = x^b \quad \text{(even power)}.
    • If bb is odd, xbx^b will have opposite signs for positive and negative xx, because: (x)b=xb(odd power).(-x)^b = -x^b \quad \text{(odd power)}.
  2. Leading Coefficient aa:

    • a>0a > 0: The function axbax^b will have a positive sign for large positive xx (if bb is even or odd).
    • a<0a < 0: The function axbax^b will have a negative sign for large positive xx (if bb is even or odd).
  3. Behavior at Limits:

    • The problem states: limxf(x)=,limxf(x)=.\lim_{x \to \infty} f(x) = -\infty, \quad \lim_{x \to -\infty} f(x) = -\infty.
    • For f(x)=axbf(x) = ax^b, both limits being negative implies that:
      • a<0a < 0, since the negative leading coefficient makes the function trend toward negative infinity for both large positive and large negative xx.
      • bb must be even, because only an even exponent ensures that xbx^b has the same behavior for both xx \to \infty and xx \to -\infty.

Correct Answer:

The value of bb must be even to ensure the same behavior for xx \to \infty and xx \to -\infty, as stated in C.

Therefore, the correct choice is:

C. The value of bb must be even, because as xx increases without bound or decreases without bound, the end behaviors of ff are the same.


Let me know if you have any questions about this solution.

Here are 5 related questions to deepen your understanding:

  1. What would change if limxf(x)=\lim_{x \to -\infty} f(x) = \infty instead?
  2. How does the sign of aa affect the graph of a polynomial function?
  3. What is the behavior of the function if bb is odd but a>0a > 0?
  4. Why does an even bb result in symmetric end behavior for positive and negative xx?
  5. How does the degree of the polynomial affect its dominance as x±x \to \pm\infty?

Tip: Always analyze the parity (odd/even nature) of the exponent when determining end behavior in polynomial functions!

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Math Problem Analysis

Mathematical Concepts

Polynomials
Limits
End Behavior of Functions

Formulas

f(x) = ax^b

Theorems

Odd and Even Function Behavior

Suitable Grade Level

Grades 10-12