Math Problem Statement

Let X be a discrete variable that generates ordinal data defined by the probability mass function f(k) = (λ^k)(e^-k) / k! where k is a natural number and λ=1. What is P(X>2)

Solution

We are given a probability mass function (PMF) for a discrete random variable XX that generates ordinal data:

f(k)=λkeλk!whereλ=1,kNf(k) = \frac{\lambda^k e^{-\lambda}}{k!} \quad \text{where} \quad \lambda = 1, \, k \in \mathbb{N}

This is the PMF of a Poisson distribution with parameter λ=1\lambda = 1.

We are tasked with finding P(X>2)P(X > 2), which represents the probability that the random variable XX takes values greater than 2. The cumulative probability P(X>2)P(X > 2) can be calculated as:

P(X>2)=1P(X2)P(X > 2) = 1 - P(X \leq 2)

Where P(X2)P(X \leq 2) is the cumulative probability for X=0,1,2X = 0, 1, 2. Let's compute this step by step:

Step 1: Compute P(X2)P(X \leq 2)

The cumulative probability P(X2)P(X \leq 2) is the sum of probabilities for X=0,1,2X = 0, 1, 2:

P(X2)=P(X=0)+P(X=1)+P(X=2)P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

Using the Poisson distribution PMF:

  • P(X=0)=10e10!=e1P(X = 0) = \frac{1^0 e^{-1}}{0!} = e^{-1}
  • P(X=1)=11e11!=e1P(X = 1) = \frac{1^1 e^{-1}}{1!} = e^{-1}
  • P(X=2)=12e12!=e12P(X = 2) = \frac{1^2 e^{-1}}{2!} = \frac{e^{-1}}{2}

Now, sum these probabilities:

P(X2)=e1+e1+e12=e1(1+1+12)=e1×52P(X \leq 2) = e^{-1} + e^{-1} + \frac{e^{-1}}{2} = e^{-1} \left(1 + 1 + \frac{1}{2}\right) = e^{-1} \times \frac{5}{2}

Thus:

P(X2)=52e1P(X \leq 2) = \frac{5}{2} e^{-1}

Step 2: Compute P(X>2)P(X > 2)

Now, use the complement rule:

P(X>2)=1P(X2)=152e1P(X > 2) = 1 - P(X \leq 2) = 1 - \frac{5}{2} e^{-1}

Final Answer:

P(X>2)=152e1P(X > 2) = 1 - \frac{5}{2} e^{-1}

This is the exact expression for P(X>2)P(X > 2). If you want a numerical approximation, you can plug in the value of e10.3679e^{-1} \approx 0.3679:

P(X>2)152×0.3679=10.919750.08025P(X > 2) \approx 1 - \frac{5}{2} \times 0.3679 = 1 - 0.91975 \approx 0.08025

Summary:

P(X>2)0.08025P(X > 2) \approx 0.08025

Would you like further clarification or a deeper dive into any part of this calculation?

Additional Questions:

  1. How does the Poisson distribution relate to other common distributions like the binomial or normal distribution?
  2. How would you compute P(X=k)P(X = k) for other values of kk?
  3. What is the expected value and variance of a Poisson distribution with λ=1\lambda = 1?
  4. How would you use this distribution to model events occurring at a fixed rate over time?
  5. What is the cumulative distribution function (CDF) of a Poisson distribution?

Tip:

For quick calculations, remember that the Poisson distribution is often used to model rare events happening at a constant average rate, especially in contexts like traffic flows, call centers, and biological processes.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Poisson Distribution
Discrete Probability Distributions

Formulas

f(k) = (λ^k * e^(-λ)) / k!
P(X > 2) = 1 - P(X <= 2)

Theorems

Poisson Distribution

Suitable Grade Level

Grades 10-12