Math Problem Statement
Let X be a discrete variable that generates ordinal data defined by the probability mass function f(k) = (λ^k)(e^-k) / k! where k is a natural number and λ=1. What is P(X>2)
Solution
We are given a probability mass function (PMF) for a discrete random variable that generates ordinal data:
This is the PMF of a Poisson distribution with parameter .
We are tasked with finding , which represents the probability that the random variable takes values greater than 2. The cumulative probability can be calculated as:
Where is the cumulative probability for . Let's compute this step by step:
Step 1: Compute
The cumulative probability is the sum of probabilities for :
Using the Poisson distribution PMF:
Now, sum these probabilities:
Thus:
Step 2: Compute
Now, use the complement rule:
Final Answer:
This is the exact expression for . If you want a numerical approximation, you can plug in the value of :
Summary:
Would you like further clarification or a deeper dive into any part of this calculation?
Additional Questions:
- How does the Poisson distribution relate to other common distributions like the binomial or normal distribution?
- How would you compute for other values of ?
- What is the expected value and variance of a Poisson distribution with ?
- How would you use this distribution to model events occurring at a fixed rate over time?
- What is the cumulative distribution function (CDF) of a Poisson distribution?
Tip:
For quick calculations, remember that the Poisson distribution is often used to model rare events happening at a constant average rate, especially in contexts like traffic flows, call centers, and biological processes.
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Math Problem Analysis
Mathematical Concepts
Probability Theory
Poisson Distribution
Discrete Probability Distributions
Formulas
f(k) = (λ^k * e^(-λ)) / k!
P(X > 2) = 1 - P(X <= 2)
Theorems
Poisson Distribution
Suitable Grade Level
Grades 10-12