Math Problem Statement

Find the points of intersection of the graphs of the functions y=5sin(6x) and y=0 for x between x=0 and x=3π12 (enter your answer as a comma separated list) 0, pi/6 0, pi/6 0,π6 0, 6 π ​

Then find the area bounded by the curves y=5sin(6x) and y=0 for x between x=0 and x=3π12

Solution

Step 1: Finding the Points of Intersection

We are tasked with finding the points of intersection between the graphs of y=5sin(6x)y = 5\sin(6x) and y=0y = 0 in the interval x[0,3π12]x \in [0, \frac{3\pi}{12}].

To do this, set the two equations equal to each other: 5sin(6x)=05\sin(6x) = 0

This simplifies to: sin(6x)=0\sin(6x) = 0

The general solution for sin(6x)=0\sin(6x) = 0 is: 6x=nπfornZ6x = n\pi \quad \text{for} \quad n \in \mathbb{Z} x=nπ6x = \frac{n\pi}{6}

Now, we need to find the values of xx in the interval [0,3π12]\left[0, \frac{3\pi}{12} \right], which simplifies to [0,π4]\left[0, \frac{\pi}{4}\right].

For n=0n = 0, we get x=0x = 0.

For n=1n = 1, we get: x=π6x = \frac{\pi}{6}

There are no more values of xx in the given interval.

Thus, the points of intersection are: x=0,π6x = 0, \frac{\pi}{6}

Step 2: Finding the Area Bounded by the Curves

We now find the area between y=5sin(6x)y = 5\sin(6x) and y=0y = 0 in the interval x[0,3π12]x \in [0, \frac{3\pi}{12}], i.e., x[0,π4]x \in [0, \frac{\pi}{4}].

The area under the curve is given by the integral: Area=0π65sin(6x)dx\text{Area} = \int_0^{\frac{\pi}{6}} 5\sin(6x) \, dx

To solve this integral: 5sin(6x)dx=56cos(6x)\int 5\sin(6x) \, dx = -\frac{5}{6}\cos(6x)

Now, evaluate this from x=0x = 0 to x=π6x = \frac{\pi}{6}: Area=[56cos(6x)]0π6\text{Area} = \left[-\frac{5}{6}\cos(6x)\right]_0^{\frac{\pi}{6}} =56(cos(6π6)cos(0))= -\frac{5}{6} \left(\cos(6 \cdot \frac{\pi}{6}) - \cos(0)\right) =56(cos(π)cos(0))= -\frac{5}{6} \left(\cos(\pi) - \cos(0)\right) =56(11)= -\frac{5}{6} \left(-1 - 1\right) =56(2)=106=53= -\frac{5}{6} \cdot (-2) = \frac{10}{6} = \frac{5}{3}

Thus, the area bounded by the curves is 53\frac{5}{3}.

Final Answers:

  • Points of intersection: 0,π60, \frac{\pi}{6}
  • Area bounded by the curves: 53\frac{5}{3}

Do you want further details on any step or have additional questions?

Here are 5 related questions to explore:

  1. How would the area change if the function were y=10sin(6x)y = 10\sin(6x)?
  2. What are the solutions to sin(6x)=0\sin(6x) = 0 for xx in [0,π][0, \pi]?
  3. How do you find the length of the curve y=5sin(6x)y = 5\sin(6x) between two points?
  4. What is the maximum value of y=5sin(6x)y = 5\sin(6x) and at which xx does it occur?
  5. How would you compute the area between two sinusoidal functions, like y=5sin(6x)y = 5\sin(6x) and ( y

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Integration
Area between Curves

Formulas

sin(θ) = 0 at θ = nπ
Area under curve using integration: ∫ f(x) dx

Theorems

Trigonometric identities
Definite Integration

Suitable Grade Level

Grades 10-12