Math Problem Statement

A sample of 5 months of sales data provided the following information. Month 1 2 3 4 5 Units Sold 96 96 86 93 99 (a) Develop a point estimate of the population mean number of units sold per month. (b) Develop a point estimate of the population standard deviation. (Round your answer to two decimal places.)

Solution

Let's solve the problem step by step.

(a) Point Estimate of the Population Mean

The point estimate of the population mean is simply the sample mean of the data. To calculate it, we sum all the values of units sold and then divide by the number of months.

Given data for units sold over 5 months:

  • x1=96x_1 = 96
  • x2=96x_2 = 96
  • x3=86x_3 = 86
  • x4=93x_4 = 93
  • x5=99x_5 = 99

The sample mean (xˉ\bar{x}) is:

xˉ=x1+x2+x3+x4+x55=96+96+86+93+995=4705=94\bar{x} = \frac{x_1 + x_2 + x_3 + x_4 + x_5}{5} = \frac{96 + 96 + 86 + 93 + 99}{5} = \frac{470}{5} = 94

So, the point estimate of the population mean is 94 units sold per month.


(b) Point Estimate of the Population Standard Deviation

The sample standard deviation (ss) is given by the formula:

s=1n1i=1n(xixˉ)2s = \sqrt{\frac{1}{n-1} \sum_{i=1}^{n} (x_i - \bar{x})^2}

Where:

  • n=5n = 5 (number of months)
  • xˉ=94\bar{x} = 94 (sample mean)

Let's calculate it step by step.

  1. Calculate the differences from the mean for each data point:

    • 9694=296 - 94 = 2
    • 9694=296 - 94 = 2
    • 8694=886 - 94 = -8
    • 9394=193 - 94 = -1
    • 9994=599 - 94 = 5
  2. Square these differences:

    • 22=42^2 = 4
    • 22=42^2 = 4
    • (8)2=64(-8)^2 = 64
    • (1)2=1(-1)^2 = 1
    • 52=255^2 = 25
  3. Sum the squared differences: 4+4+64+1+25=984 + 4 + 64 + 1 + 25 = 98

  4. Divide by n1n-1 (which is 4): 984=24.5\frac{98}{4} = 24.5

  5. Take the square root to find the standard deviation: s=24.54.95s = \sqrt{24.5} \approx 4.95

So, the point estimate of the population standard deviation is 4.95 units.


Summary:

  • (a) The point estimate of the population mean is 94 units sold per month.
  • (b) The point estimate of the population standard deviation is 4.95 units.

Do you want more details on the calculations or have any other questions?


Here are 5 related questions you might be interested in:

  1. How can we calculate a confidence interval for the population mean?
  2. What is the difference between sample standard deviation and population standard deviation?
  3. How would the standard deviation change if the dataset included more months?
  4. What is the relationship between variance and standard deviation?
  5. How can we test whether this sample mean is significantly different from a hypothesized population mean?

Tip: Always check whether you are using a sample or population when calculating standard deviation, as the formulas slightly differ.

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Math Problem Analysis

Mathematical Concepts

Statistics
Descriptive Statistics
Point Estimate
Sample Mean
Sample Standard Deviation

Formulas

Sample Mean formula: x̄ = (Σxi) / n
Sample Standard Deviation formula: s = sqrt[(Σ(xi - x̄)²) / (n - 1)]

Theorems

Point Estimation Theorem
Sample Standard Deviation Theory

Suitable Grade Level

Grades 9-12