Math Problem Statement

A scientist receiving a new sample of plutonium knows that the sample will not be of use to him after 9090 percent of the radioactive material in the sample has disintegrated.

If the half-life of this particular plutonium isotope is 113113 days, for how many days after the sample arrives will the scientist be able to make use of the plutonium?

Solution

We are tasked with determining how many days the scientist can use the plutonium, given that its half-life is 113 days and it becomes unusable after 90% of the radioactive material has disintegrated.

Step 1: Radioactive Decay Formula

The general formula for radioactive decay is:

N(t)=N0eλtN(t) = N_0 \cdot e^{-\lambda t}

Where:

  • N(t)N(t) is the remaining amount of substance at time tt.
  • N0N_0 is the initial amount of substance.
  • λ\lambda is the decay constant.
  • tt is the time in days.

Step 2: Decay Constant (λ\lambda)

The decay constant λ\lambda is related to the half-life T12T_{\frac{1}{2}} by the formula:

λ=ln(2)T12\lambda = \frac{\ln(2)}{T_{\frac{1}{2}}}

For this problem, the half-life is T12=113T_{\frac{1}{2}} = 113 days. Thus, the decay constant is:

λ=ln(2)1130.006133\lambda = \frac{\ln(2)}{113} \approx 0.006133

Step 3: Fraction of Remaining Plutonium

The scientist can no longer use the plutonium after 90% of it has decayed, meaning that only 10% of the original amount remains. Thus, we set:

N(t)=0.1N0N(t) = 0.1 \cdot N_0

Substituting this into the decay formula:

0.1N0=N0eλt0.1 \cdot N_0 = N_0 \cdot e^{-\lambda t}

Canceling N0N_0 from both sides:

0.1=eλt0.1 = e^{-\lambda t}

Step 4: Solve for tt

To solve for tt, take the natural logarithm of both sides:

ln(0.1)=λt\ln(0.1) = -\lambda t

Thus,

t=ln(0.1)λt = \frac{\ln(0.1)}{-\lambda}

Substituting λ0.006133\lambda \approx 0.006133:

t=ln(0.1)0.0061332.3025850.006133375.46 dayst = \frac{\ln(0.1)}{-0.006133} \approx \frac{-2.302585}{-0.006133} \approx 375.46 \text{ days}

Final Answer:

The scientist will be able to use the plutonium for approximately 375 days before 90% of it disintegrates.

Would you like further details on any of these steps or have any questions?


Here are 5 questions to deepen your understanding:

  1. How does the decay constant relate to the half-life of a substance?
  2. What happens to the remaining quantity of a substance after multiple half-lives?
  3. Why is the natural logarithm used in radioactive decay problems?
  4. What would the usable time be if the half-life were different?
  5. How does the percentage of disintegration affect the time a sample can be used?

Tip: Always double-check if you're using natural logarithms (base ee) or common logarithms (base 10) in decay-related calculations.

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Math Problem Analysis

Mathematical Concepts

Exponential Decay
Radioactive Decay
Half-Life

Formulas

N(t) = N_0 * e^(-λt)
λ = ln(2) / T_1/2
t = ln(N/N_0) / -λ

Theorems

Radioactive Decay Law

Suitable Grade Level

Grades 10-12