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The image contains the following math word problem:

"A plumber has a fixed call-out charge of $80 and has an hourly rate of $60. Work out the total charge, $ C $, for a job that takes $ L $ hours in which the cost of materials and parts is $ K $."

### Solution:

The total charge $ C $ can be calculated as the sum of the fixed call-out charge, the hourly rate for the number of hours worked, and the cost of materials and parts.

The formula for the total charge $ C $ is:

\[
C = 80 + 60L + K
\]

Where:
- 80 is the fixed call-out charge,
- $ 60L $ is the hourly charge, with $ L $ being the number of hours worked,
- $ K $ is the cost of materials and parts.

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Here are five related questions to expand on this problem:

1. If the job takes 3 hours and the cost of materials is $150, what is the total charge?
2. How would the formula change if the hourly rate increased to $70?
3. What if the plumber had a discount on the materials, reducing $ K $ by 10%? How would that

A plumber has a fixed call-out charge of $80 and has an hourly rate of $60. Work out the total charge, C, for a job that takes L hours in which the cost of materials and parts is K.

Learn how to calculate the total charge for a plumber's job with a fixed call-out fee of $80, an hourly rate of $60, and material costs. Suitable for Grades 6-8, this problem covers basic linear equations.

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