https://file.aiquickdraw.com/mathbot/file/1727647828283p5sch4zv.jpg

The problem shown in the image is:

"A plane carrying 336 people was \( \frac{4}{5} \) full. How many passengers would need to be added so that the plane was 95% full?"

### Solution:

1. Let the total capacity of the plane be \( C \).
2. We know that the plane is \( \frac{4}{5} \) full with 336 passengers, meaning:
   \[
   \frac{4}{5}C = 336
   \]
   Solving for \( C \):
   \[
   C = \frac{336 \times 5}{4} = 420
   \]
   So, the total capacity of the plane is 420 passengers.

3. To make the plane 95% full, we need to calculate 95% of the total capacity:
   \[
   0.95 \times 420 = 399
   \]
   So, 399 passengers would make the plane 95% full.

4. The number of passengers that need to be added is:
   \[
   399 - 336 = 63
   \]

### Final Answer:
63 passengers need to be added to make the plane 95% full.

Would you like further clarification on any steps? Here are 5 related questions:

1. How would the calculation change if the plane were 90% full instead of 95%?
2. Can we find how many passengers were in the plane if it was half full?
3. What if the plane was \( \frac{3}{4} \) full, how would that affect the number of additional passengers needed?
4. How would we adjust the problem if the total capacity of the plane was unknown, but we knew the number of passengers for different percentages?
5. Could you explain how fractions like \( \frac{4}{5} \) are converted to percentages in this context?

**Tip**: Always convert fractions or percentages into decimal form when working with practical problems involving proportions!

A plane carrying 336 people was 4/5 full. How many passengers would need to be added so that the plane was 95% full?

Learn how to calculate the number of passengers needed to make a plane, which is currently 4/5 full with 336 passengers, 95% full. This problem involves algebra, fractions, and percentages, suitable for students in Grades 7-9.

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