Math Problem Statement
A block of massslides down a 30.0° incline which is 3.60 m high. At the bottom, it strikes a block of masswhich is at rest on a horizontal surface. (Assume a smooth transition at the bottom of the incline.) If the collision is elastic, and friction can be ignored, determine (a) the speeds of the two blocks after the collision, and (b) how far back up the incline the smaller mass will go.
Solution
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Math Problem Analysis
Mathematical Concepts
Conservation of Energy
Elastic Collisions
Newton's Laws
Formulas
Potential energy: PE = mgh
Kinetic energy: KE = (1/2)mv^2
Momentum conservation: m1v1 + m2v2 = m1v1' + m2v2'
Velocity after elastic collision: v1' = (m1 - m2)/(m1 + m2) * v1, v2' = 2m1/(m1 + m2) * v1
Maximum height after collision: h = (v1'^2) / (2g)
Theorems
Law of Conservation of Energy
Law of Conservation of Momentum
Suitable Grade Level
Undergraduate Level (Physics)
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