To find the frequency ($f$) of a photon, you can use the relationship between energy ($E$) and frequency, given by Planck's equation:

$E = h \cdot f$

Where:

• $E$ is the energy of the photon (5.39 × 10⁻¹⁹ J),
• $h$ is Planck's constant (6.626 × 10⁻³⁴ J·s),
• $f$ is the frequency of the photon.

To solve for $f$:

$f = \frac{E}{h}$

Now, substitute the given values:

$f = \frac{5.39 \times 10^{-19}}{6.626 \times 10^{-34}}$

Let me calculate this for you.The frequency of the photon is approximately $8.13 \times 10^{14}$ Hz.

Would you like further details or have any questions about the calculation?

Here are 5 related questions for further exploration:

1. How does energy relate to the wavelength of a photon?
2. What is the speed of light, and how can it be used to calculate the wavelength from frequency?
3. How do photons with different frequencies affect the electromagnetic spectrum?
4. What is the energy of a photon with a frequency of $5 \times 10^{14}$ Hz?
5. How does Planck's constant play a role in quantum mechanics?

Tip: Remember, higher frequency photons have higher energy, while lower frequency photons have less energy.