The course of a yachting race is in the shape of a triangle with sides that measure
A = 4
3
10
miles,

B = 3
7
10
miles,
and
C = 2
1
2
miles.
Find the total length of the course in miles.

To find the total length of the course, you simply need to add the lengths of the three sides of the triangular course. Here's the addition of the sides:

\[
\text{Total length} = A + B + C
\]

Given:
- \( A = 4 \frac{3}{10} \, \text{miles} = 4.3 \, \text{miles} \)
- \( B = 3 \frac{7}{10} \, \text{miles} = 3.7 \, \text{miles} \)
- \( C = 2 \frac{1}{2} \, \text{miles} = 2.5 \, \text{miles} \)

Now, let's sum these values:

\[
\text{Total length} = 4.3 + 3.7 + 2.5 = 10.5 \, \text{miles}
\]

Thus, the total length of the course is **10.5 miles**.

Would you like any further details or have any questions?

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Here are 5 related questions to extend your understanding:
1. How would the total length change if one side of the triangle increased by 1 mile?
2. Can you find the area of the triangular course using Heron's formula?
3. What is the perimeter of a triangle, and how does it apply to this scenario?
4. If the race followed a circular course, how would you calculate its length?
5. How would changing the shape of the course to a quadrilateral affect the total length?

**Tip:** When working with mixed fractions, always convert them to decimal form for easier calculations.

The course of a yachting race is in the shape of a triangle with sides that measure A = 4 3/10 miles, B = 3 7/10 miles, and C = 2 1/2 miles. Find the total length of the course in miles.

Learn how to calculate the total length of a triangular yachting racecourse with sides of 4 3/10 miles, 3 7/10 miles, and 2 1/2 miles. This problem explains the geometry concept of perimeter and shows how to add mixed fractions. Ideal for students in Grades 5-7.

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