Math Problem Statement

A rectangular field is y feet wide. The length of the field is four times longer than the width. If the perimeter of the field is 86 feet, which of the following equations represents the given information?

Solution

The problem asks us to find the correct equation that represents the given information about the rectangular field.

  1. The width of the rectangular field is given as yy feet.
  2. The length of the field is four times the width, so the length is 4y4y feet.
  3. The perimeter of the field is 86 feet.

The formula for the perimeter PP of a rectangle is: P=2(length+width)P = 2(\text{length} + \text{width})

Substituting the values: 86=2(4y+y)86 = 2(4y + y)

Simplifying: 86=2(5y)86 = 2(5y) 86=10y86 = 10y

Solving for yy: y=8610=8.6feety = \frac{86}{10} = 8.6 \, \text{feet}

Now, let's check which equation represents this situation. Since the perimeter formula simplifies to 86=10y86 = 10y, the correct equation should follow from that logic.

  • Option A: y+y+4y+4y=86y + y + 4y + 4y = 86 – This simplifies to 10y=8610y = 86, which is correct.

Thus, Option A is the correct equation.

Do you want further details or have any questions?

Related Questions:

  1. How do you calculate the area of the rectangular field with the given dimensions?
  2. If the width yy was increased by 2 feet, how would the perimeter change?
  3. What would happen to the perimeter if the length was tripled instead of being four times the width?
  4. How can you generalize the perimeter equation for any multiple of the width?
  5. How would the perimeter change if the dimensions were doubled?

Tip:

When solving problems involving perimeter, always apply the formula 2(length+width)2(\text{length} + \text{width}) to ensure accuracy in combining terms.

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Math Problem Analysis

Mathematical Concepts

Geometry
Perimeter of a Rectangle
Linear Equations

Formulas

P = 2(length + width)

Theorems

Formula for the Perimeter of a Rectangle

Suitable Grade Level

Grade 6-8