The shape in the image is a rectangle, with a length of 10.1 meters and a width of 6.3 meters.

The formula for the perimeter $P$ of a rectangle is:

$P = 2 \times (\text{Length} + \text{Width})$

Substituting the values:

$P = 2 \times (10.1 \, \text{m} + 6.3 \, \text{m}) = 2 \times 16.4 \, \text{m} = 32.8 \, \text{m}$

Thus, the perimeter of the rectangle is 32.8 meters.

Would you like any additional details or clarification on this?

Here are 5 related questions for you:

1. What is the area of this rectangle?
2. How would the perimeter change if the length increased by 2 meters?
3. How does the perimeter formula apply to other polygons, such as triangles or pentagons?
4. Can you find the diagonal of the rectangle using Pythagoras' theorem?
5. What is the perimeter of a square with the same area as this rectangle?

Tip: Remember, the perimeter is the total distance around the shape, adding all the sides together!