Math Problem Statement
Solution
This problem involves a pendulum with a ball of mass attached to a string of length . The string makes a 30° angle with the horizontal at point . Let’s break down the questions:
Part (a)
You need to draw and label the forces acting on the ball when it is at point . There are two main forces:
- Gravitational force (): Acts downward (vertically).
- Tension in the string (): Acts along the string, directed towards the pivot point.
Part (b)
To determine the speed of the ball at point , we can use energy conservation principles, assuming the ball starts from rest at its highest point (horizontal position).
- The potential energy at the horizontal position is entirely converted to kinetic and potential energy at point .
The total mechanical energy at the top is purely gravitational potential energy: At point , the height above the lowest point is , and the energy is the sum of kinetic and potential energy:
Equating the initial and final energies: Simplifying:
Part (c)
To determine the tension in the string at point , apply Newton’s second law in the radial direction. The forces acting along the string are the tension and the radial component of gravity.
Using: Substitute from part (b):
Part (d)
The tangential acceleration is due to the tangential component of the gravitational force:
Let me know if you'd like further clarifications or details! Here are some related questions you could explore:
- How would the motion change if the mass of the ball doubled?
- What happens to the speed at point if the angle were increased to 45°?
- How does the tension vary if the string is shortened?
- What would happen if frictional forces were considered?
- How is the period of the pendulum affected by the string length?
Tip: Always start energy conservation problems by identifying the reference points for potential energy.
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Math Problem Analysis
Mathematical Concepts
Energy conservation
Forces
Circular motion
Formulas
E_initial = mgh = mgℓ
E_final = (1/2)mv^2 + mg(h)
v = sqrt(2gℓcos(30°))
T - mg cos(30°) = mv^2 / ℓ
T = 3mg cos(30°)
a_tangential = g sin(30°)
Theorems
Conservation of Mechanical Energy
Newton's Second Law
Suitable Grade Level
Grades 11-12
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