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This problem involves a pendulum with a ball of mass \( m \) attached to a string of length \( \ell \). The string makes a 30° angle with the horizontal at point \( P \). Let’s break down the questions:

### Part (a)
You need to draw and label the forces acting on the ball when it is at point \( P \). There are two main forces:

1. **Gravitational force (\( mg \))**: Acts downward (vertically).
2. **Tension in the string (\( T \))**: Acts along the string, directed towards the pivot point.

### Part (b)
To determine the speed of the ball at point \( P \), we can use energy conservation principles, assuming the ball starts from rest at its highest point (horizontal position).

- The potential energy at the horizontal position is entirely converted to kinetic and potential energy at point \( P \).

The total mechanical energy at the top is purely gravitational potential energy:
\[
E_{\text{initial}} = mgh = mg\ell
\]
At point \( P \), the height \( h \) above the lowest point is \( h = \ell - \ell \cos(30^\circ) \), and the energy is the sum of kinetic and potential energy:
\[
E_{\text{final}} = \frac{1}{2}mv^2 + mg(\ell - \ell \cos(30^\circ))
\]

Equating the initial and final energies:
\[
mg\ell = \frac{1}{2}mv^2 + mg(\ell - \ell \cos(30^\circ))
\]
Simplifying:
\[
\frac{1}{2}mv^2 = mg\ell \cos(30^\circ)
\]
\[
v^2 = 2g\ell \cos(30^\circ)
\]
\[
v = \sqrt{2g\ell \cos(30^\circ)}
\]

### Part (c)
To determine the tension in the string at point \( P \), apply Newton’s second law in the radial direction. The forces acting along the string are the tension and the radial component of gravity.

Using:
\[
T - mg \cos(30^\circ) = \frac{mv^2}{\ell}
\]
Substitute \( v^2 \) from part (b):
\[
T - mg \cos(30^\circ) = \frac{m(2g\ell \cos(30^\circ))}{\ell}
\]
\[
T = 3mg \cos(30^\circ)
\]

### Part (d)
The tangential acceleration \( a_{\text{tangential}} \) is due to the tangential component of the gravitational force:
\[
a_{\text{tangential}} = g \sin(30^\circ)
\]

Let me know if you'd like further clarifications or details! Here are some related questions you could explore:

1. How would the motion change if the mass of the ball doubled?
2. What happens to the speed at point \( P \) if the angle were increased to 45°?
3. How does the tension vary if the string is shortened?
4. What would happen if frictional forces were considered?
5. How is the period of the pendulum affected by the string length?

**Tip**: Always start energy conservation problems by identifying the reference points for potential energy.

A pendulum consisting of a small heavy ball of mass m at the end of a string of length ℓ is released from a horizontal position. When the ball is at point P, the string forms an angle of 30° with the horizontal. Determine the forces acting at P, the speed at P, the tension in the string, and the tangential acceleration.

Solve a physics pendulum problem involving energy conservation and forces. Determine the speed, tension in the string, and tangential acceleration when the string forms a 30° angle with the horizontal. Suitable for advanced high school students.

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