Math Problem Statement
Solution
Let's break down the given question into parts and solve them:
Question 2:
a) Obtain the Principal Disjunctive Normal Form (PDNF) of
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Step 1: Express the given logical expression in simpler terms:
- is equivalent to (Implication equivalence).
- is equivalent to (Biconditional equivalence).
Now the expression becomes:
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Step 2: Apply distributive laws: To simplify this, we need to distribute the terms across the conjunction. We'll distribute over the disjunction .
Distribute this: [ [(\neg P \lor Q) \land (Q \land R)] \lor [(\neg P \lor Q) \land (\neg Q \land \neg R)] ]
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Step 3: Further simplify each part:
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The first part can be expanded as: This simplifies to , since is common in both terms.
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The second part simplifies to: because the term and cannot both be true.
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Step 4: Final result: The final disjunctive normal form (PDNF) is:
b) Show that and are logically equivalent.
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Negation of disjunction:
- By De Morgan's Law, is equivalent to:
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Conclusion:
- Since both expressions and simplify to the same result, they are logically equivalent.
Would you like a more detailed explanation or have any other questions on these topics?
Here are 5 related questions you could explore:
- What is the Principal Conjunctive Normal Form (PCNF) of the same expression?
- How can we prove De Morgan's laws using truth tables?
- How do you convert any logical expression to its disjunctive normal form?
- What is the difference between PDNF and PCNF in logic?
- How do biconditional statements differ from simple conjunctions?
Tip: Always apply De Morgan's laws when dealing with negations of conjunctions or disjunctions—it helps in simplifying complex logical expressions efficiently.
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Math Problem Analysis
Mathematical Concepts
Propositional Logic
Logical Equivalences
Disjunctive Normal Form
Formulas
Implication: P → Q ≡ ¬P ∨ Q
Biconditional: Q ↔ R ≡ (Q ∧ R) ∨ (¬Q ∧ ¬R)
De Morgan’s Law: ¬(P ∨ Q) ≡ ¬P ∧ ¬Q
Theorems
De Morgan’s Law
Distributive Property of Logic
Suitable Grade Level
Undergraduate Logic/Mathematics
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