Math Problem Statement

Answer with patrialis fraction

Solution

To solve the integral using partial fraction decomposition, we first decompose the fraction:

2x3+5x2+16x(5x4+8x2+16).\frac{2x^3 + 5x^2 + 16}{x(5x^4 + 8x^2 + 16)}.

Step-by-Step Partial Fraction Decomposition

  1. Factor the Denominator:

    The denominator is already partially factored:

    x(5x4+8x2+16).x(5x^4 + 8x^2 + 16).

    Now, we consider the expression 5x4+8x2+165x^4 + 8x^2 + 16 as a quadratic in terms of x2x^2. Let y=x2y = x^2, then we have:

    5y2+8y+16.5y^2 + 8y + 16.

    Since this quadratic has no real roots (its discriminant 824516=264<08^2 - 4 \cdot 5 \cdot 16 = -264 < 0), it is irreducible over the reals. Thus, we treat 5x4+8x2+165x^4 + 8x^2 + 16 as an irreducible quadratic in x2x^2.

  2. Set Up the Partial Fractions:

    Now, express the fraction as a sum of partial fractions:

    2x3+5x2+16x(5x4+8x2+16)=Ax+Bx+C5x4+8x2+16.\frac{2x^3 + 5x^2 + 16}{x(5x^4 + 8x^2 + 16)} = \frac{A}{x} + \frac{Bx + C}{5x^4 + 8x^2 + 16}.

    Multiply through by the denominator to clear the fractions:

    2x3+5x2+16=A(5x4+8x2+16)+(Bx+C)x.2x^3 + 5x^2 + 16 = A(5x^4 + 8x^2 + 16) + (Bx + C)x.

    Expand and collect like terms:

    2x3+5x2+16=(5A)x4+(8A+B)x3+(16A+C)x2.2x^3 + 5x^2 + 16 = (5A)x^4 + (8A + B)x^3 + (16A + C)x^2.

  3. Equate Coefficients:

    Now, match coefficients for each power of xx:

    • Coefficient of x4x^4: 5A=0    A=05A = 0 \implies A = 0.
    • Coefficient of x3x^3: 8A+B=2    0+B=2    B=28A + B = 2 \implies 0 + B = 2 \implies B = 2.
    • Coefficient of x2x^2: 16A+C=5    0+C=5    C=516A + C = 5 \implies 0 + C = 5 \implies C = 5.

    So, we have A=0A = 0, B=2B = 2, and C=5C = 5.

    The decomposition becomes:

    2x3+5x2+16x(5x4+8x2+16)=2x+55x4+8x2+16.\frac{2x^3 + 5x^2 + 16}{x(5x^4 + 8x^2 + 16)} = \frac{2x + 5}{5x^4 + 8x^2 + 16}.

  4. Rewrite the Integral:

    The integral now is:

    2x+55x4+8x2+16dx.\int \frac{2x + 5}{5x^4 + 8x^2 + 16} \, dx.

Solving the Integral

Now, let's split the integral into two parts:

2x5x4+8x2+16dx+55x4+8x2+16dx.\int \frac{2x}{5x^4 + 8x^2 + 16} \, dx + \int \frac{5}{5x^4 + 8x^2 + 16} \, dx.

For the first integral:

  • Substitute u=5x4+8x2+16u = 5x^4 + 8x^2 + 16, du=(20x3+16x)dx=4x(5x2+4)dxdu = (20x^3 + 16x) dx = 4x(5x^2 + 4) dx, which simplifies this part.

For the second integral:

  • A suitable trigonometric substitution or table integration may apply, depending on its specific form.

Would you like to proceed with solving these integrals, or do you have a preference for a particular approach?