Math Problem Statement

What is the partial derivative of a function f with respect to x, given the expression in the image?

Solution

The expression in the image is the partial derivative of a function ff with respect to xx, given as:

fx=sin(xy2)y2(xy2)cos(xy2)y2(xy2)2\frac{\partial f}{\partial x} = \frac{-\sin(xy^2) \cdot y^2 \cdot (xy^2) - \cos(xy^2) \cdot y^2}{(xy^2)^2}

Let's analyze it step by step:

Numerator:

  1. The term involves two parts: sin(xy2)y2(xy2)andcos(xy2)y2-\sin(xy^2) \cdot y^2 \cdot (xy^2) \quad \text{and} \quad -\cos(xy^2) \cdot y^2
    • The first part is the product of the sine function, sin(xy2)\sin(xy^2), multiplied by y2y^2 and xy2xy^2.
    • The second part is cos(xy2)-\cos(xy^2) multiplied by y2y^2.

Denominator:

  1. The denominator is (xy2)2(xy^2)^2, which means we square xy2xy^2.

Simplification Approach:

This expression could potentially be simplified further by factoring common terms in the numerator, but it would depend on the function structure.

Would you like a more detailed step-by-step simplification or further clarification on any specific part of this derivative?

Here are five possible questions based on this context:

  1. What is the original function ff from which this derivative is obtained?
  2. How can we simplify the numerator by factoring common terms?
  3. What is the role of the chain rule in finding this partial derivative?
  4. Can the denominator (xy2)2(xy^2)^2 be simplified in any context?
  5. How would this expression behave for specific values of xx and yy?

Tip: When simplifying trigonometric derivatives involving products, always look for common terms in both the numerator and denominator.

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Math Problem Analysis

Mathematical Concepts

Calculus
Partial Derivatives
Trigonometric Functions

Formulas

Partial derivative formula
Chain rule for differentiation

Theorems

Chain rule
Product rule

Suitable Grade Level

Undergraduate