X2+2x+4y-11=0 equation of a parabola in general form, make it in standard form, opening of the graph, vertex, length of lactus rectum, value of p, focus, endpoints of LR, directrix, axis of symmetry 

The given equation is:

\[
x^2 + 2x + 4y - 11 = 0
\]

Let's transform this into the standard form for a parabola, and then find the required properties like the opening direction, vertex, length of the latus rectum, value of \( p \), focus, endpoints of the latus rectum, directrix, and axis of symmetry.

### Step 1: Rearranging the equation
We can rewrite the equation by grouping the \( x \)-terms on the left and isolating the \( y \)-terms on the right:

\[
x^2 + 2x = 11 - 4y
\]

Now, we need to complete the square for the \( x \)-terms.

### Step 2: Completing the square
To complete the square for \( x^2 + 2x \), take half of the coefficient of \( x \) (which is 2), square it, and add it to both sides:

\[
x^2 + 2x + 1 = 11 - 4y + 1
\]

This simplifies to:

\[
(x + 1)^2 = 12 - 4y
\]

Now isolate \( y \):

\[
(x + 1)^2 = -4(y - 3)
\]

### Step 3: Standard form of the parabola
The equation is now in the standard form of a parabola:

\[
(x + 1)^2 = -4(y - 3)
\]

This is a vertical parabola, and it opens **downward** because of the negative sign in front of the \( 4(y - 3) \).

### Step 4: Vertex
The vertex of the parabola is at the point \( (-1, 3) \), derived from the standard form \( (x - h)^2 = 4p(y - k) \), where \( (h, k) \) is the vertex.

### Step 5: Value of \( p \)
From the equation \( (x + 1)^2 = -4(y - 3) \), we have \( 4p = -4 \), so \( p = -1 \).

### Step 6: Focus
The focus is located at \( (h, k + p) \). Since \( h = -1 \), \( k = 3 \), and \( p = -1 \), the focus is at:

\[
\text{Focus} = (-1, 3 - 1) = (-1, 2)
\]

### Step 7: Directrix
The directrix is the line \( y = k - p \). Therefore, the directrix is:

\[
\text{Directrix} = y = 3 + 1 = 4
\]

### Step 8: Axis of symmetry
The axis of symmetry is the vertical line passing through the vertex, which is:

\[
\text{Axis of symmetry} = x = -1
\]

### Step 9: Length of the latus rectum
The length of the latus rectum is given by \( |4p| \). Since \( p = -1 \), the length of the latus rectum is:

\[
\text{Length of latus rectum} = |4(-1)| = 4
\]

### Step 10: Endpoints of the latus rectum
The endpoints of the latus rectum are located at \( (h \pm 2p, k + p) \). Using \( h = -1 \), \( k = 3 \), and \( p = -1 \):

\[
\text{Endpoints of latus rectum} = (-1 \pm 2, 2) = (-3, 2) \text{ and } (1, 2)
\]

### Summary:
- **Opening**: Downward
- **Vertex**: \( (-1, 3) \)
- **Focus**: \( (-1, 2) \)
- **Directrix**: \( y = 4 \)
- **Axis of symmetry**: \( x = -1 \)
- **Length of latus rectum**: 4
- **Endpoints of latus rectum**: \( (-3, 2) \) and \( (1, 2) \)

Would you like more details on any of these concepts?

Here are five related questions:
1. How do you complete the square for other conic sections, like ellipses or hyperbolas?
2. What is the significance of the value \( p \) in parabolas?
3. How do the properties of horizontal parabolas differ from vertical parabolas?
4. Can you find the equation of the parabola given its focus and directrix?
5. What are the differences between the general form and standard form of conic sections?

**Tip**: For parabolas, the sign of \( p \) determines the direction of opening—positive for upward/rightward and negative for downward/leftward.

X^2+2x+4y-11=0 equation of a parabola in general form, make it in standard form, opening of the graph, vertex, length of lactus rectum, value of p, focus, endpoints of LR, directrix, axis of symmetry

Learn how to convert the parabola equation X^2 + 2x + 4y - 11 = 0 from its general form to standard form, determine its vertex, opening direction, focus, directrix, and other key properties. Suitable for students in Grades 9-12.

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