Math Problem Statement
2, 3, 5, 9, 9, 11, 12, 12, 13, 13, 14, 15, 15, 16, 19, 19, 20, 21, 25, 26, 32, 32, 38, 40, 48, 49, 49, 52, 86, 97. The Q1 is 12 and the Q2 is 38. The median is 19. Find the lower and upper outlier boundaries.
Solution
To find the lower and upper outlier boundaries using the given data, we use the Interquartile Range (IQR) method.
The steps are as follows:
1. Calculate the IQR
The Interquartile Range (IQR) is the difference between the third quartile (Q3) and the first quartile (Q1):
From the information you provided:
- (which is actually , based on the context)
Thus:
2. Calculate the outlier boundaries
Lower boundary:
The lower boundary is calculated using the formula:
Upper boundary:
The upper boundary is calculated using the formula:
3. Conclusion:
- The lower outlier boundary is , meaning there are no lower outliers since all data points are positive.
- The upper outlier boundary is 77, meaning any data points above 77 are considered outliers.
Outliers:
From your data set, the only value greater than 77 is 86 and 97, so these are outliers.
Would you like more details or have any questions? Here are 5 related questions you can explore:
- How do quartiles divide a data set?
- What happens if the IQR is very small?
- How do extreme outliers affect statistical analysis?
- How would you visualize this data using a box plot?
- Can the IQR method detect all types of outliers?
Tip: The IQR method is a robust way to detect outliers because it is not influenced by extreme values like the mean and standard deviation methods.
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Math Problem Analysis
Mathematical Concepts
Statistics
Quartiles
Outliers
Interquartile Range (IQR)
Formulas
Interquartile Range (IQR) = Q3 - Q1
Lower Outlier Boundary = Q1 - 1.5 × IQR
Upper Outlier Boundary = Q3 + 1.5 × IQR
Theorems
IQR Method for Outlier Detection
Suitable Grade Level
Grades 10-12
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