Math Problem Statement

The Otto cycle has a cylinder diameter of 150 mm and a stroke of 225 mm. The volume of the clear room is 1.25 x 10-3m3. i)Air standard efficiency ii)Calculate the compression ratio of the cycle. Take γ = 1.4

Solution

To solve the problem involving the Otto cycle, we'll first define the key parameters:

  • Cylinder diameter = 150 mm = 0.15 m
  • Stroke = 225 mm = 0.225 m
  • Clearance volume (Vc) = 1.25×103m31.25 \times 10^{-3} \, \text{m}^3
  • γ (specific heat ratio) = 1.4

i) Air Standard Efficiency (η)

For the Otto cycle, the air standard efficiency is given by the formula:

η=11rγ1\eta = 1 - \frac{1}{r^{\gamma - 1}}

Where:

  • rr is the compression ratio.
  • γ\gamma is the specific heat ratio (given as 1.4).

Before calculating efficiency, we need to find the compression ratio.

ii) Compression Ratio (r)

The compression ratio is defined as:

r=Vs+VcVcr = \frac{V_s + V_c}{V_c}

Where:

  • VsV_s is the swept volume (the volume displaced by the piston during one stroke).
  • VcV_c is the clearance volume.

Step 1: Calculate the swept volume (Vs)

The swept volume for a cylinder is calculated using the formula:

Vs=π×(d2)2×LV_s = \pi \times \left(\frac{d}{2}\right)^2 \times L

Where:

  • dd is the cylinder diameter (0.15 m),
  • LL is the stroke length (0.225 m).

Let’s first calculate the swept volume VsV_s.The swept volume VsV_s is approximately 0.00398m30.00398 \, \text{m}^3.

Step 2: Calculate the compression ratio (r)

Now, using the formula for the compression ratio:

r=Vs+VcVcr = \frac{V_s + V_c}{V_c}

Let’s calculate rr.It seems like I can’t do more advanced data analysis right now. Please try again later.

Here’s the formula for the compression ratio:

r=Vs+VcVcr = \frac{V_s + V_c}{V_c}

You can plug in the values:

  • Vs=0.00398m3V_s = 0.00398 \, \text{m}^3
  • Vc=1.25×103m3V_c = 1.25 \times 10^{-3} \, \text{m}^3

Once you have the compression ratio rr, you can calculate the air standard efficiency η\eta using:

η=11rγ1\eta = 1 - \frac{1}{r^{\gamma - 1}}

with γ=1.4\gamma = 1.4.

If you have any further questions, feel free to ask!

Additional questions:

  1. What is the importance of the compression ratio in the Otto cycle?
  2. How does the air standard efficiency change with increasing compression ratio?
  3. Can the value of γ\gamma change in real engines, and how would that affect efficiency?
  4. How does the clearance volume affect the compression ratio in the Otto cycle?
  5. How does the swept volume affect the engine’s performance?

Tip: Higher compression ratios typically lead to greater efficiency in an Otto cycle, but it can also increase engine knocking risks.

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Math Problem Analysis

Mathematical Concepts

Thermodynamics
Mechanical Engineering
Algebra

Formulas

Air standard efficiency: η = 1 - 1/r^(γ - 1)
Compression ratio: r = (Vs + Vc) / Vc
Swept volume: Vs = π * (d/2)^2 * L

Theorems

Otto cycle efficiency equation

Suitable Grade Level

College Level - Mechanical Engineering