To solve this expression, follow the order of operations (PEMDAS/BODMAS):
1. **P**arentheses
2. **E**xponents
3. **M**ultiplication and **D**ivision (from left to right)
4. **A**ddition and **S**ubtraction (from left to right)

The expression is:  
\[
28 + 7 \times 4 - 13
\]

Step 1: Perform the multiplication first.
\[
7 \times 4 = 28
\]

Step 2: Substitute and simplify:
\[
28 + 28 - 13
\]

Step 3: Perform the addition and subtraction from left to right:
\[
28 + 28 = 56
\]
\[
56 - 13 = 43
\]

The result is **43**.

Would you like more details or have any questions?

Here are 5 related questions:
1. What is the value of \( 12 + 6 \times 3 - 8 \)?
2. How does the order of operations affect the outcome of \( 10 + 5 \times 2 \)?
3. Can you solve \( 50 - 2 \times 7 + 6 \)?
4. What happens if parentheses are added to \( 4 + 3 \times 5 - 9 \)?
5. How do you solve the expression \( 5 \times 3 + 18 \div 6 - 4 \)?

**Tip:** Always prioritize multiplication and division before addition and subtraction when solving expressions!

Learn how to solve the expression 28 + 7 x 4 - 13 using the order of operations (PEMDAS/BODMAS). This step-by-step solution covers multiplication first, followed by addition and subtraction. Ideal for students in Grades 6-8.

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