Math Problem Statement
Use Figure 1 to answer question 5 and 6. 5. (goal 25) A home owner has a large open space and wants to use fencing to create a rectangular garden with 2 smaller gardens of equal size, as shown in figure 1. He has 600 feet of fencing. Write an equation A(w) describing the total area of the garden in terms of the width, w. 6. (goal 6) What dimensions should the garden enclosure have to create the maximum total area for the garden? What is the maximum possible area?
Solution
Let’s delve into solving these questions.
Question 5: Writing the Equation for Total Area
The rectangular garden is divided into 2 smaller gardens of equal size, and the fencing is 600 feet total. The fencing includes:
- Two vertical sections for the width ().
- Three horizontal sections for the length ().
The total fencing equation is:
From this, solve for in terms of :
The total area of the garden is:
Substituting into the area equation:
Simplify:
Thus, the equation for the total area is:
Question 6: Maximizing the Area
To find the dimensions for the maximum area, maximize . The formula is:
-
Differentiate with respect to :
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Set to find the critical points:
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Verify that gives a maximum by examining the second derivative:
-
Find when :
The dimensions are:
- The maximum possible area is:
Final Answers:
5.
6. Dimensions: , Maximum Area:
Do you want detailed explanations or clarifications on any step?
5 Follow-up Questions:
- What does the second derivative test tell us about a function's concavity?
- How would the solution change if the total fencing were increased or decreased?
- Could you determine the dimensions graphically instead of using calculus?
- How do you confirm that the area formula is correct for different values of ?
- What is the significance of the critical point in this problem?
Tip: When optimizing, always verify constraints to ensure feasible results!
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Math Problem Analysis
Mathematical Concepts
Quadratic Optimization
Algebra
Functions
Formulas
Perimeter equation: 2w + 3l = 600
Area equation: A(w) = w * l
Maximization of quadratic function A(w) = (-2/3)w^2 + 200w
Theorems
Second Derivative Test
Suitable Grade Level
Grades 10-12
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