Math Problem Statement

The figure above shows a rectangle inscribed in a semicircle with a radius of 20. The area of such a rectangle is given by A(x) = 2x√(400 - x^2), where the width of the rectangle is 2x. It can be shown that A'(x) = -2x^2 / √(400 - x^2) + 2√(400 - x^2), and A has critical values of -20, -10√2, 10√2, and 20. It can also be shown that A'(x) changes from positive to negative at x = 10√2. Which of the following statements is true? A) The inscribed rectangle with maximum area has dimensions 10√2 by 10√2. B) The inscribed rectangle with minimum area has dimensions 10√2 by 10√2. C) The inscribed rectangle with maximum area has dimensions 20√2 by 10√2. D) The inscribed rectangle with minimum area has dimensions 20√2 by 10√2.

Solution

The problem asks us to analyze a rectangle inscribed in a semicircle with a radius of 20. We're provided with the equation for the area A(x)=2x400x2A(x) = 2x \sqrt{400 - x^2}, which gives the area of the rectangle in terms of xx, the length of one side of the rectangle. We are also given the derivative A(x)A'(x) and critical points for A(x)A(x).

To solve this problem:

  1. Critical Points: We need to find the dimensions of the rectangle at the critical point where A(x)=0A'(x) = 0, which is provided to be x=102x = 10\sqrt{2}.

  2. Maximum and Minimum Areas: To determine which rectangle corresponds to the maximum or minimum area, we examine the second derivative or analyze the sign change of A(x)A'(x).

  3. Dimensions: For x=102x = 10\sqrt{2}, the dimensions of the rectangle are:

    • Width: 2x2x
    • Height: 400x2\sqrt{400 - x^2}

We will now compute the dimensions at x=102x = 10\sqrt{2} and verify which option is correct.

Let me proceed with these calculations. sympy as sp

Define the symbol and the equation for A(x)

x = sp.symbols('x') A = 2 * x * sp.sqrt(400 - x**2)

Compute A'(x) to check the critical points

A_prime = sp.diff(A, x)

Define x = 10*sqrt(2) to calculate the width and height of the rectangle

critical_x = 10 * sp.sqrt(2)

Calculate the width (2x) and height (sqrt(400 - x^2)) at x = 10*sqrt(2)

width = 2 * critical_x height = sp.sqrt(400 - critical_x**2)

width, heightAt the critical point x=102x = 10\sqrt{2}, the dimensions of the inscribed rectangle are:

  • Width: 20220\sqrt{2}
  • Height: 10210\sqrt{2}

Now, looking at the given options:

  • Option A: The inscribed rectangle with maximum area has dimensions 10210\sqrt{2} by 10210\sqrt{2}.
  • Option B: The inscribed rectangle with minimum area has dimensions 10210\sqrt{2} by 10210\sqrt{2}.
  • Option C: The inscribed rectangle with maximum area has dimensions 20220\sqrt{2} by 10210\sqrt{2}.
  • Option D: The inscribed rectangle with minimum area has dimensions 20220\sqrt{2} by 10210\sqrt{2}.

The correct answer is Option C, which corresponds to the maximum area.

Would you like further details or have any questions about the steps? Here are some related questions to explore further:

  1. How do we confirm whether a critical point is a maximum or a minimum using the second derivative test?
  2. How can we derive the general formula for the area of an inscribed rectangle in any semicircle?
  3. What role does symmetry play in the dimensions of the rectangle?
  4. What happens when the value of xx approaches 20 in this problem?
  5. How do we analyze the behavior of A(x)A(x) at the boundaries (i.e., when x=0x = 0 or x=20x = 20)?

Tip: When dealing with optimization problems like this, always start by finding the derivative, setting it equal to zero to find critical points, and then use the second derivative test or analyze the behavior of the function at the critical points.

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Math Problem Analysis

Mathematical Concepts

Calculus
Optimization
Critical Points
Geometry of Inscribed Figures

Formulas

Area of rectangle: A(x) = 2x√(400 - x^2)
Derivative of area: A'(x) = -2x^2 / √(400 - x^2) + 2√(400 - x^2)
Critical points: Solve A'(x) = 0

Theorems

Optimization using critical points
Behavior of functions based on derivatives

Suitable Grade Level

Grades 11-12 or early college