Math Problem Statement

A manufacturer cuts squares from the corners of a rectangular piece of sheet metal that measures 2 inches by 6 inches. The manufacturer folds the metal upward to make an open-topped box. Letting x represent the side-lengths (in inches) of the squares, find the value of x that maximizes the volume of the box and determine the maximum volume.

Solution

To solve this problem, let's break down the steps to find the value of xx that maximizes the volume of the box created.

Step-by-Step Solution

  1. Define Dimensions of the Original Sheet:

    • The sheet is 22 inches by 66 inches.
  2. Define the Dimensions of the Box After Folding:

    • When squares of side length xx are cut from each corner, the length, width, and height of the resulting box change:
      • Length: 62x6 - 2x
      • Width: 22x2 - 2x
      • Height: xx (since xx is the height after folding the edges up)
  3. Express the Volume of the Box as a Function of xx:

    • The volume VV of the box can be expressed as: V(x)=(62x)(22x)xV(x) = (6 - 2x)(2 - 2x) \cdot x
    • Expanding this expression: V(x)=(1212x+4x2)xV(x) = (12 - 12x + 4x^2) \cdot x V(x)=4x312x2+12xV(x) = 4x^3 - 12x^2 + 12x
  4. Find the Value of xx that Maximizes V(x)V(x):

    • To find the maximum volume, we need to find the critical points by taking the derivative of V(x)V(x) with respect to xx and setting it to zero. V(x)=12x224x+12V'(x) = 12x^2 - 24x + 12
    • Setting V(x)=0V'(x) = 0 to find critical points: 12x224x+12=012x^2 - 24x + 12 = 0
    • Simplifying: x22x+1=0x^2 - 2x + 1 = 0 (x1)2=0(x - 1)^2 = 0 x=1x = 1
  5. Verify the Value of xx and Calculate the Maximum Volume:

    • Substitute x=1x = 1 back into the volume function: V(1)=4(1)312(1)2+12(1)V(1) = 4(1)^3 - 12(1)^2 + 12(1) V(1)=412+12=4V(1) = 4 - 12 + 12 = 4

Final Answer

  • The value of xx that maximizes the volume is 1 inch.
  • The maximum volume of the box is 4 cubic inches.

Would you like a more detailed breakdown of any part of the solution?

Related Questions

  1. How would the volume formula change if the original sheet dimensions were different?
  2. What would happen to the volume if the side length xx is larger than 1 inch?
  3. How can we verify that x=1x = 1 gives a maximum volume rather than a minimum?
  4. What is the impact on volume if the sheet was square rather than rectangular?
  5. Can this problem be solved using a different optimization technique?

Tip

For problems involving optimization, remember to always check the critical points by setting the derivative to zero and confirm if they yield a maximum or minimum using the second derivative or by analyzing the function's behavior.

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Math Problem Analysis

Mathematical Concepts

Optimization
Volume of a Box
Quadratic Equations
Derivatives

Formulas

Volume of a box V = (Length)(Width)(Height)
Volume function V(x) = (6 - 2x)(2 - 2x)(x)
Derivative of volume function V'(x) to find maximum volume

Theorems

First Derivative Test for Maximum/Minimum Values

Suitable Grade Level

High School (Grades 10-12)