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The given numbers are:

396, 462, 572, 427, 671, 264.

To find the odd one out, let's analyze the sum of the digits of each number:

1. **396**: \( 3 + 9 + 6 = 18 \) (even)
2. **462**: \( 4 + 6 + 2 = 12 \) (even)
3. **572**: \( 5 + 7 + 2 = 14 \) (even)
4. **427**: \( 4 + 2 + 7 = 13 \) (odd)
5. **671**: \( 6 + 7 + 1 = 14 \) (even)
6. **264**: \( 2 + 6 + 4 = 12 \) (even)

From the results, the number **427** stands out because the sum of its digits is odd, whereas the sum of the digits of all the other numbers is even.

Therefore, **427** is the odd one out.

Would you like further details, or do you have any questions? 

Here are some related questions:
1. What are other methods to find the odd one out in a set of numbers?
2. How do you determine if a number is divisible by certain factors based on its digits?
3. Can you analyze numbers by their prime factorization to find patterns?
4. What are some common tricks in finding odd numbers in such puzzles?
5. How can digit sums help in identifying properties of larger numbers?

**Tip**: Always check the sum of digits when looking for patterns involving "odd one out." It's a common feature in number puzzles.

In the following question, four words have been given of which three are alike in some way and one is different. Choose the odd one out: 396, 462, 572, 427, 671, 264

Learn how to find the odd one out from a set of numbers by analyzing the sum of digits. In this problem, numbers like 396, 462, 572, and 671 are evaluated based on even and odd digit sums. Suitable for Grades 6-8.

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