Math Problem Statement

The lengths of movie files that are available for streaming are modeled using a normal distribution. The mean of the distribution is 170.5 minutes and the standard deviation is 19.9 minutes. V is the mean, and U and W are symmetric points around V. What percentage of the total area under the curve is shaded, and what are the values of U, V, and W?

Solution

The problem you uploaded involves a normal distribution with a mean of 170.5 minutes and a standard deviation of 19.9 minutes. You're tasked with identifying points UU, VV, and WW, which are spaced equally around the center of the normal distribution (at VV, the mean), and calculating the percentage of the total shaded area under the curve.

Step-by-step breakdown:

  1. Normal Distribution Basics:

    • Mean μ=170.5\mu = 170.5 minutes.
    • Standard deviation σ=19.9\sigma = 19.9 minutes.
  2. Identifying VV:

    • VV is the mean, located under the highest point of the bell curve. So, V=170.5V = 170.5.
  3. Identifying UU and WW:

    • UU and WW are symmetric points around the mean, such that the distance from VV to UU is the same as from VV to WW. These distances likely correspond to intervals of the standard deviation (based on the "empirical rule").
  4. Using the Empirical Rule:

    • 68% of the data falls within one standard deviation (VσV - \sigma to V+σV + \sigma).
    • 95% of the data falls within two standard deviations (V2σV - 2\sigma to V+2σV + 2\sigma).
    • 99.7% of the data falls within three standard deviations (V3σV - 3\sigma to V+3σV + 3\sigma).

From the image, it appears the points UU and WW mark an interval that might correspond to about 95% of the total area under the curve. This suggests that U=V2σU = V - 2\sigma and W=V+2σW = V + 2\sigma.

  1. Calculating UU and WW: U=V2σ=170.52(19.9)=170.539.8=130.7U = V - 2\sigma = 170.5 - 2(19.9) = 170.5 - 39.8 = 130.7 W=V+2σ=170.5+2(19.9)=170.5+39.8=210.3W = V + 2\sigma = 170.5 + 2(19.9) = 170.5 + 39.8 = 210.3

Thus, U=130.7U = 130.7, V=170.5V = 170.5, and W=210.3W = 210.3.

  1. Percentage of Area Shaded:
    • Since UU and WW correspond to two standard deviations from the mean, the percentage of the shaded area under the curve is approximately 95%.

Would you like more details on any part of the explanation?

Related Questions:

  1. How would the shaded area change if we considered only one standard deviation from the mean?
  2. What percentage of data lies outside the range of two standard deviations?
  3. If the standard deviation were increased, how would UU and WW change?
  4. How would the shape of the curve change with a smaller standard deviation?
  5. Can you explain how the empirical rule applies to non-symmetric distributions?

Tip:

When dealing with normal distributions, memorizing the empirical rule (68-95-99.7) helps in quickly estimating probabilities based on standard deviations.

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Math Problem Analysis

Mathematical Concepts

Normal Distribution
Empirical Rule
Standard Deviation

Formulas

U = V - 2σ
W = V + 2σ
Empirical Rule: 68-95-99.7 Rule

Theorems

Empirical Rule

Suitable Grade Level

Grades 10-12