Math Problem Statement
Normal Distribution: Consider a normally distributed random variable with mean 0 and standard deviation 1. How does the probability that fall within the interval [−1,1] relate to probability that fall within the interval [0,1] ?
Solution
For a normally distributed random variable with mean and standard deviation , the probability that falls within certain intervals can be related to the properties of the standard normal distribution (denoted as ).
1. Probability that falls within the interval :
We need to compute the probability , which is the area under the standard normal curve from -1 to 1:
Using the cumulative distribution function (CDF) for a standard normal distribution, we have:
So:
This means approximately 68.26% of the values of a standard normal variable fall within one standard deviation of the mean (between -1 and 1).
2. Probability that falls within the interval :
Now, we compute , which is the area under the standard normal curve from 0 to 1:
Since and , we have:
Thus, approximately 34.13% of the values of a standard normal variable fall between 0 and 1.
3. Relationship Between the Two Probabilities:
The probability of falling within is 68.26%, while the probability of falling within is 34.13%. Since the standard normal distribution is symmetric around zero, the probability that falls between -1 and 0 is also 34.13%, meaning that:
In other words, the probability of falling within is exactly twice the probability of falling within .
Would you like any further details or explanations?
Here are five related questions to explore:
- What is the probability of a standard normal variable falling between -2 and 2?
- How does the probability change if the interval is expanded to ?
- Can you derive the probability for intervals such as using the CDF?
- What are the properties of the normal distribution that lead to symmetry?
- How does the concept of z-scores relate to probabilities in normal distribution?
Tip: Always remember that about 68.26%, 95.44%, and 99.73% of the data falls within 1, 2, and 3 standard deviations of the mean, respectively, in a standard normal distribution.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Probability
Normal Distribution
Standard Normal Distribution
Symmetry of Normal Distribution
Formulas
P(-1 ≤ Z ≤ 1) = P(Z ≤ 1) - P(Z ≤ -1)
P(0 ≤ Z ≤ 1) = P(Z ≤ 1) - P(Z ≤ 0)
P(-1 ≤ Z ≤ 1) = 2 * P(0 ≤ Z ≤ 1)
Theorems
68-95-99.7 Rule (Empirical Rule)
Properties of Standard Normal Distribution
Suitable Grade Level
Grades 10-12