Math Problem Statement

  3. The serum cholesterol levels of a population of 18-year-olds follow a normal distribution with a mean of 178 mg/dL and a standard deviation of 32 mg/dL. 

a) What proportion of the 18-year-olds have serum cholesterol values between 141 mg/dL and 196 mg/dL? 

b) Suppose we were choose at random from the population a large number of five 18-year-olds each. In what proportion of the groups would the group mean cholesterol value be between 141 mg/dL and 196 mg/dL? 

Solution

Let's solve the problem using the properties of the normal distribution.

Given:

  • Mean (μ\mu) = 178 mg/dL
  • Standard deviation (σ\sigma) = 32 mg/dL

Part a) Proportion of 18-year-olds with serum cholesterol values between 141 mg/dL and 196 mg/dL

We need to find P(141<X<196)P(141 < X < 196), where XX is the serum cholesterol level.

  1. Calculate the Z-scores for 141 mg/dL and 196 mg/dL: Z1=14117832Z_1 = \frac{141 - 178}{32} Z2=19617832Z_2 = \frac{196 - 178}{32}

  2. Find the probabilities corresponding to these Z-scores using the standard normal distribution.

  3. The proportion of the population within this range is the difference between the probabilities for Z2Z_2 and Z1Z_1.

Part b) Proportion of groups where the mean cholesterol value is between 141 mg/dL and 196 mg/dL

Here, we need to find the proportion of groups where the mean cholesterol level of five 18-year-olds falls between 141 mg/dL and 196 mg/dL.

  1. Standard Error of the Mean (σXˉ\sigma_{\bar{X}}): σXˉ=σn=325\sigma_{\bar{X}} = \frac{\sigma}{\sqrt{n}} = \frac{32}{\sqrt{5}}

  2. Calculate the Z-scores for the sample mean (141 mg/dL and 196 mg/dL): Z1=141178σXˉZ_1 = \frac{141 - 178}{\sigma_{\bar{X}}} Z2=196178σXˉZ_2 = \frac{196 - 178}{\sigma_{\bar{X}}}

  3. Find the proportion as in Part a by determining the difference between the probabilities corresponding to Z2Z_2 and Z1Z_1.

Let's compute these values.Here are the results:

Part a) Proportion of 18-year-olds with serum cholesterol values between 141 mg/dL and 196 mg/dL

The proportion of 18-year-olds who have serum cholesterol levels between 141 mg/dL and 196 mg/dL is approximately 0.589 (or 58.9%).

Part b) Proportion of groups where the mean cholesterol value is between 141 mg/dL and 196 mg/dL

The proportion of groups (where each group consists of five 18-year-olds) with a mean cholesterol level between 141 mg/dL and 196 mg/dL is approximately 0.891 (or 89.1%).

Summary:

  • Part a: About 58.9% of 18-year-olds have serum cholesterol levels between 141 mg/dL and 196 mg/dL.
  • Part b: About 89.1% of groups of five 18-year-olds will have a mean cholesterol level within this range.

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Math Problem Analysis

Mathematical Concepts

Normal Distribution
Z-score
Central Limit Theorem

Formulas

Z-score formula
Standard Error of the Mean formula

Theorems

Central Limit Theorem

Suitable Grade Level

Undergraduate