Math Problem Statement

You said: Two forces, F⃗ 1 and F⃗ 2 lift a bucket whose mass is m = 5.7 kg vertically upward. The magnitude of the gravitational acceleration is 9.80 m/s2 . The magnitude of F1 is unknown. The magnitude of F2 = 93.0 N . Now you can apply Newton's 2nd Law in the y- axis to the find the bucket's acceleration ay.

Solution

To solve this problem, we will apply Newton's Second Law in the vertical direction (y-axis) to find the bucket's acceleration aya_y.

Step-by-Step Solution:

  1. Identify the forces acting on the bucket:

    • Gravitational force: Fg=mg=5.7kg9.80m/s2=55.86NF_g = m \cdot g = 5.7 \, \text{kg} \cdot 9.80 \, \text{m/s}^2 = 55.86 \, \text{N} (acting downward).
    • Force F1F_1 (acting upward), magnitude unknown.
    • Force F2=93.0NF_2 = 93.0 \, \text{N} (acting upward).
  2. Net force in the y-axis: The net force FnetF_{\text{net}} acting on the bucket is the sum of the forces in the vertical direction: Fnet=F1+F2FgF_{\text{net}} = F_1 + F_2 - F_g Where F1F_1 and F2F_2 are upward forces, and FgF_g is the downward gravitational force.

  3. Newton's Second Law: According to Newton’s second law: Fnet=mayF_{\text{net}} = m \cdot a_y So, F1+F2Fg=mayF_1 + F_2 - F_g = m \cdot a_y Substitute the known values: F1+93.0N55.86N=5.7kgayF_1 + 93.0 \, \text{N} - 55.86 \, \text{N} = 5.7 \, \text{kg} \cdot a_y Simplifying: F1+37.14N=5.7kgayF_1 + 37.14 \, \text{N} = 5.7 \, \text{kg} \cdot a_y

  4. Final equation: You now have a relationship between F1F_1 and the bucket's acceleration aya_y. To find aya_y, you need more information, such as the value of F1F_1. Without that, you can only express the acceleration in terms of F1F_1: ay=F1+37.14N5.7kga_y = \frac{F_1 + 37.14 \, \text{N}}{5.7 \, \text{kg}}

Would you like to continue with more details or ask additional questions? Here are some questions that can expand on this:

  1. How does Newton’s second law apply when multiple forces are acting on a body?
  2. How can we solve for F1F_1 if we know the bucket's acceleration?
  3. How does gravity affect objects moving vertically upward?
  4. What are the conditions for equilibrium in this system?
  5. What happens if the acceleration is zero (i.e., the system is in equilibrium)?

Tip: Always ensure to consider the direction of forces carefully. Positive and negative signs are crucial in vector equations!

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Math Problem Analysis

Mathematical Concepts

Newton's Second Law
Forces
Gravitational Force
Acceleration

Formulas

F_net = F₁ + F₂ - F_g
F_net = m * a_y
F_g = m * g

Theorems

Newton's Second Law of Motion

Suitable Grade Level

Grades 9-12