Math Problem Statement

V 2 . 0 3 4

ا ل ش ك ل

ا ل ع ش ر ي

ا ل ط ب ي ع ي

ل ل ر ق م

4 5 . 2

ه و O a .

0 . 4 5 x 1 0 1

ي ا

ب .

0 . 4 5 x 1 0

2

ي ا

ج . 0 . 4 5 X 1 0

1

ي ا

د .

0 . 0 4 5

ب ا س ت خ د ا م

ت ق ر ي ب

ث ل ا ث ي

ا ل أ ر ق ا م

ل ل ت ق ر ي ب

ا ل أ و ل

ل ج ذ ر

ا ل م ع ا د ل ة f ( x )

0 ،

ب ط ر ي ق ة

ن ي و ت ن

ي ك و ن p 1

= 3 . 5 2

م ع pe

3 .

إ ذ ا

ك ا ن ت f ( 3 )

= 0 . 4 8 ،

ف أ ي

م م ا

ي ل ي

ي م ك ن

أ ن

ي ك و ن

ق ي م ة f ' ( 3 ) a .

UD 0 2

0 . 9 2 3

ي ا

ب .

0 . 8 2 2

ي ا

ج .

0 . 9 2

ي ا

د .

0 . 9 2 3

Solution

The problem appears to be related to Newton's method, which is used to approximate the roots of a function f(x)f(x).

Given:

  • p1=3.52p_1 = 3.52 with pe=3p_e = 3
  • f(3)=0.48f(3) = 0.48

The question asks for the value of f(3)f'(3), the derivative of f(x)f(x) at x=3x = 3.

Newton's method formula for finding the next approximation pn+1p_{n+1} is:

pn+1=pnf(pn)f(pn)p_{n+1} = p_n - \frac{f(p_n)}{f'(p_n)}

Using the information provided:

\quad \text{and} \quad p_e = 3$$ Given that $$p_2 = p_e = 3$$, this implies: $$3 = 3.52 - \frac{0.48}{f'(3)}$$ To solve for $$f'(3)$$: $$\frac{0.48}{f'(3)} = 3.52 - 3 = 0.52$$ $$f'(3) = \frac{0.48}{0.52}$$ Calculating this: $$f'(3) = \frac{0.48}{0.52} \approx -0.923$$ So the correct choice for $$f'(3)$$ is **Option A: -0.923**. Would you like more details on Newton's method or any other part of this problem? Here are some follow-up questions that might interest you: 1. How does Newton's method work for finding roots? 2. What are the limitations of Newton's method? 3. How do you interpret the derivative $$f'(x)$$ in this context? 4. What happens if $$f'(x)$$ is close to zero in Newton's method? 5. How would a different initial guess $$p_1$$ affect the convergence? **Tip:** Newton's method is highly sensitive to the choice of the initial guess. A poor guess can lead to divergence or slow convergence.

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Math Problem Analysis

Mathematical Concepts

Newton's Method
Derivatives

Formulas

Newton's method formula: p_{n+1} = p_n - \frac{f(p_n)}{f'(p_n)}

Theorems

-

Suitable Grade Level

Advanced High School