The expression you provided involves multiplication:

\[
(1.80 \times 10^{-4} \, \text{m}^3) \times (2 \times 10^7 \, \text{kg})
\]

Let's multiply the coefficients and handle the powers of 10 separately:

\[
(1.80 \times 2) \times (10^{-4} \times 10^7) = 3.60 \times 10^3
\]

So, the result of the multiplication is:

\[
3.60 \times 10^3 \, \text{m}^3 \cdot \text{kg}
\]

This simplifies to:

\[
3600 \, \text{m}^3 \cdot \text{kg}
\]

Would you like further details or have any questions? 

Here are five related questions:
1. What are the properties of powers of 10 when multiplying and dividing?
2. How do you convert between different units when working with scientific notation?
3. What is the significance of the base in scientific notation?
4. How would the result change if one of the values were negative?
5. How do exponents behave when dealing with fractional values?

**Tip**: When multiplying powers of 10, remember that you add the exponents!

This guide explains how to multiply two quantities using scientific notation: 1.80 x 10^-4 m^3 and 2 x 10^7 kg. The step-by-step solution covers multiplying coefficients and powers of 10, leading to a result of 3600 m^3·kg. Suitable for Grades 9-10 students studying scientific notation and powers of 10.

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