To solve the expression \((0.26 \times 10^{-25}) \times 15\), you can follow these steps:

1. **Multiply the coefficients**: Multiply \(0.26\) by \(15\).
2. **Keep the power of 10 unchanged**: The exponent part, \(10^{-25}\), remains the same during the multiplication.

Let's compute this:

\[
0.26 \times 15 = 3.9
\]

So the expression becomes:

\[
3.9 \times 10^{-25} \, \text{g}
\]

This is the simplified form of the expression. The mass is now \(3.9 \times 10^{-25}\) grams.

### Would you like more details or have any questions?

Here are five related questions:
1. What would happen if you divided \((0.26 \times 10^{-25})\) by 15 instead of multiplying?
2. How does multiplying by 15 affect the exponent in scientific notation?
3. How would you express this result as a decimal number?
4. What are the rules for multiplying numbers in scientific notation?
5. How does the final result compare to the original expression in terms of magnitude?

**Tip:** When multiplying numbers in scientific notation, you only multiply the coefficients and keep the power of 10 the same, unless you're multiplying two powers of 10, which would require adding the exponents.

Learn how to multiply numbers in scientific notation with (0.26 × 10^-25) × 15. Understand the steps involved, including keeping the exponent unchanged. Suitable for Grades 9-12 students and anyone interested in scientific notation calculations.

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