 \dfrac{4}{5} \times \left(-\dfrac{2}{9}\right) 

To multiply two fractions, we multiply the numerators together and the denominators together. Here’s how we solve the expression:

\[
\frac{4}{5} \times \left(-\frac{2}{9}\right) = \frac{4 \times (-2)}{5 \times 9}
\]

Now calculate:

\[
\frac{4 \times (-2)}{5 \times 9} = \frac{-8}{45}
\]

Thus, the product of \(\frac{4}{5}\) and \(-\frac{2}{9}\) is:

\[
\boxed{-\frac{8}{45}}
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you multiply mixed numbers?
2. What happens when you divide fractions instead of multiplying?
3. How do you simplify fractions after multiplication?
4. How would you handle this if one fraction was negative but not both?
5. What is the result if you multiply \(\frac{4}{5}\) by \(\frac{3}{7}\)?

**Tip:** When multiplying fractions, always simplify the fractions if possible before or after performing the multiplication!

\dfrac{4}{5} \times \left(-\dfrac{2}{9}\right)

Learn how to multiply the fractions \(\dfrac{4}{5}\) and \(-\dfrac{2}{9}\) with a detailed step-by-step solution. This problem focuses on key concepts like multiplying fractions and handling negative numbers, suitable for students in Grades 6-8.

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