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Let's solve the given expression \((13x + 3)(13x - 3)\).

This is a difference of squares. The general formula for this is:

\[
(a + b)(a - b) = a^2 - b^2
\]

In our case:
- \( a = 13x \)
- \( b = 3 \)

Now, apply the difference of squares formula:

\[
(13x + 3)(13x - 3) = (13x)^2 - (3)^2 = 169x^2 - 9
\]

So, the correct answer is:

\[
\boxed{D. 169x^2 - 9}
\]

Would you like further details on the process, or do you have any questions?

Here are 5 related questions:
1. What is the difference of squares formula?
2. Can this method be applied to any binomial pair?
3. What happens if the signs in both binomials are the same?
4. How can we recognize the difference of squares in an expression?
5. Can we apply the distributive property (FOIL) to verify the answer?

**Tip**: The difference of squares formula is a shortcut for quickly multiplying two conjugates!

Learn how to multiply the binomials (13x + 3)(13x - 3) using the difference of squares formula. This algebra problem is suitable for students in Grades 8-10 and demonstrates the application of key polynomial multiplication concepts.

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