https://file.aiquickdraw.com/mathbot/file/1729411399654segzm132.jpg

Let's go through each of the multi-step problems from the image:

### Problem 1: Sweets in Bags
- **Part a**: There are 12 sweets in a bag, and a group of friends has 16 bags.
  - Total sweets = \(12 \times 16 = 192\)
  - If they eat 9 sweets: \(192 - 9 = 183\)
  - **Answer**: 183 sweets left.
  
- **Part b**: Same 16 bags of sweets (192 total).
  - If they get 9 bags instead: \(12 \times 9 = 108\)
  - **Answer**: 108 sweets.

### Problem 2: Ron and Mo Saving Money
- **Part a**: Ron saves £3 every week, Mo saves £4 every week.
  - After 13 weeks:
    - Ron saves \(3 \times 13 = 39\) 
    - Mo saves \(4 \times 13 = 52\)
    - Total savings = \(39 + 52 = 91\)
  - **Answer**: £91 saved in total.
  
- **Part b**: Console costs £343, combined they save £7 per week.
  - To save £343: \(343 \div 7 = 49\) weeks.
  - **Answer**: 49 weeks.

### Problem 3: Textbooks in Boxes
- The school has 561 textbooks, each box holds 24.
  - Full boxes = \(561 \div 24 = 23\) full boxes, remainder 9 textbooks left.
  - **Answer**: 23 full boxes.

### Problem 4: Car Distance
- Car travels 13 miles in 15 minutes.
  - Speed: \(13 \div 15 = 0.867 \) miles per minute.
  - In 3 hours (180 minutes): \(0.867 \times 180 = 156.06\) miles.
  - **Answer**: 156 miles.

### Problem 5: Sharing Marbles
- Nijah and 8 friends (9 people) have 3 bags of 123 marbles each.
  - Total marbles = \(3 \times 123 = 369\)
  - Each person gets: \(369 \div 9 = 41\)
  - **Answer**: 41 marbles each.

### Problem 6: Perimeter of Octagons
- The total perimeter of the pattern is 640 cm, and the pattern is made up of regular octagons.
  - Let the perimeter of each octagon be \(P\), and suppose there are \(N\) octagons.
  - Each octagon's perimeter: \(P = 640 / N\) (but the image doesn't provide the exact count of octagons, we need that to compute further).

### Problem 7: Water Bottle Packs
- A school needs to buy enough water for 268 pupils.
  - Packs of 6 cost £4, packs of 9 cost £5.
  - Total bottles needed: \(268 \div 6 = 45\) packs of 6 or \(268 \div 9 = 30\) packs of 9.
  - Comparing costs: \(45 \times 4 = 180\) for 6-packs and \(30 \times 5 = 150\) for 9-packs.
  - Cheaper option: 9-packs.
  - Difference in price: \(180 - 150 = 30\).
  - **Answer**: It’s £30 cheaper.

### Problem 8: Sticker Books
- Sticker book A has \(5 \times 12 = 60\) stickers per page, and 6 pages: \(60 \times 6 = 360\) stickers in book A.
- Sticker book B has \(9 \times 16 = 144\) stickers per page, and 8 pages: \(144 \times 8 = 1152\) stickers in book B.
- Difference: \(1152 - 360 = 792\).
  - **Answer**: Book B holds 792 more stickers than book A.

### Problem 9: Card Game Puzzle (Target 120)
- You can use the cards \(12, 3, 5, 32, 50, 8, 1\) and different operations to make 120.
  - For example: \(12 \times 8 + 32 = 120\).

Do you want more details on any particular problem? Here are 5 related questions:
1. How would the solution to problem 2 change if Mo saved £5 instead of £4 per week?
2. Can you think of another way to arrange the cards in problem 9 to get 120?
3. If the school in problem 7 bought 2 extra bottles, how would the cost change?
4. How would the mileage change in problem 4 if the car traveled at a slightly slower speed?
5. How does the perimeter of the individual octagons in problem 6 affect the total perimeter of the pattern?

**Tip**: When tackling word problems, always break them down step by step to avoid missing important details.

Solve multi-step math problems, including calculating sweets in bags, saving money for a game console, determining full boxes of textbooks, calculating travel distance, sharing marbles, finding perimeters of octagons, comparing costs of water packs, sticker book capacity, and card game puzzles.

Solve multi-step math word problems involving sweets in bags, saving for a game console, car travel distance, textbook calculations, and marbles distribution. Includes perimeter and cost comparison problems, suitable for Grades 4-6.

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