Math Problem Statement

Для комплексных чисел z1 = 3(cos(π/9) + i sin(π/9)) и z2 = 5(cos(π/10) + i sin(π/10)) найти модуль числа z1z2.

Solution

We are tasked with finding the modulus of the product of two complex numbers z1z_1 and z2z_2, where the numbers are given in trigonometric (polar) form as:

z1=3(cosπ9+isinπ9)z_1 = 3 \left( \cos \frac{\pi}{9} + i \sin \frac{\pi}{9} \right) z2=5(cosπ10+isinπ10)z_2 = 5 \left( \cos \frac{\pi}{10} + i \sin \frac{\pi}{10} \right)

Key Steps:

  1. Modulus of a Product: The modulus of a product of two complex numbers is the product of their moduli: z1z2=z1z2|z_1 z_2| = |z_1| \cdot |z_2|

  2. Compute the Moduli:

    • The modulus of z1z_1 is the coefficient before the trigonometric terms, z1=3|z_1| = 3.
    • Similarly, the modulus of z2z_2 is z2=5|z_2| = 5.
  3. Compute the Result: z1z2=z1z2=35=15|z_1 z_2| = |z_1| \cdot |z_2| = 3 \cdot 5 = 15

Final Answer:

The modulus of z1z2z_1 z_2 is 15.


Would you like a more detailed breakdown of the process or related examples? Here are 5 questions to expand your understanding:

  1. How is the modulus of a complex number in polar form derived?
  2. Why does the argument of a product of complex numbers add in polar form?
  3. Can we represent these numbers in Cartesian form and verify the result?
  4. How would the solution change if z1z_1 and z2z_2 were given in Cartesian form?
  5. What practical applications involve working with complex numbers in polar form?

Tip: Remember, in polar form, multiplying complex numbers simplifies to multiplying their moduli and adding their arguments!

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Polar Form
Modulus of a Complex Number

Formulas

Modulus of a product: |z1 * z2| = |z1| * |z2|
Polar form representation: z = r(cos(θ) + i sin(θ))

Theorems

The modulus of a product of complex numbers equals the product of their moduli.

Suitable Grade Level

Grades 10-12