Math Problem Statement

A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d from sea level at time t = 0 seconds is 0 in, and initially it moves downward. (Note that downward is the negative direction.) Give the equation modeling the displacement d as a function of time t.

Solution

To model the displacement dd of the buoy as a function of time tt, we will use the equation for simple harmonic motion. The general form of the equation is:

d(t)=Acos(ωt+ϕ)d(t) = A \cos(\omega t + \phi)

where:

  • AA is the amplitude,
  • ω\omega is the angular frequency,
  • ϕ\phi is the phase shift.

Given:

  • The amplitude AA is 8 inches.
  • The period TT is 2 seconds.
  • At t=0t = 0, the displacement dd is 0 inches.
  • Initially, the buoy moves downward.

Step-by-Step Solution

  1. Determine the angular frequency ω\omega: The angular frequency ω\omega is related to the period TT by the formula: ω=2πT\omega = \frac{2\pi}{T} Substituting T=2T = 2 seconds: ω=2π2=π radians per second\omega = \frac{2\pi}{2} = \pi \text{ radians per second}

  2. Determine the phase shift ϕ\phi: At t=0t = 0, d(0)=0d(0) = 0. We need to find ϕ\phi such that cos(ϕ)=0\cos(\phi) = 0.

    The cosine function is zero at ϕ=π2+kπ\phi = \frac{\pi}{2} + k\pi for any integer kk. To satisfy the condition that initially the buoy moves downward (negative direction), we choose ϕ=π2\phi = \frac{\pi}{2} because the derivative of cos\cos at π2\frac{\pi}{2} is negative, indicating a downward motion.

    Thus, ϕ=π2\phi = \frac{\pi}{2}.

  3. Write the displacement equation: Substituting A=8A = 8, ω=π\omega = \pi, and ϕ=π2\phi = \frac{\pi}{2} into the general form: d(t)=8cos(πt+π2)d(t) = 8 \cos(\pi t + \frac{\pi}{2})

  4. Simplify the equation: Using the trigonometric identity cos(x+π2)=sin(x)\cos(x + \frac{\pi}{2}) = -\sin(x), we can simplify the equation: d(t)=8cos(πt+π2)=8(sin(πt))=8sin(πt)d(t) = 8 \cos(\pi t + \frac{\pi}{2}) = 8(-\sin(\pi t)) = -8 \sin(\pi t)

Final Equation

d(t)=8sin(πt)d(t) = -8 \sin(\pi t)

This equation models the displacement dd of the buoy from sea level as a function of time tt.

Would you like more details or have any questions?

Here are 5 more questions you might be interested in:

  1. How do you derive the period of a simple harmonic oscillator from its angular frequency?
  2. Can you explain the significance of phase shift in simple harmonic motion?
  3. What are the differences between sine and cosine functions in modeling periodic motion?
  4. How can you determine the velocity of an object in simple harmonic motion?
  5. How does the amplitude affect the energy in simple harmonic motion?

Tip: When dealing with harmonic motion, always check the initial conditions to correctly determine the phase shift.

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Math Problem Analysis

Mathematical Concepts

Simple Harmonic Motion
Trigonometry

Formulas

Simple Harmonic Motion equation: d(t) = A * cos(ωt + φ)

Theorems

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Suitable Grade Level

Grades 10-12