Math Problem Statement

You need a 10% alcohol solution. On hand, you have a 480 mL of a 5% alcohol mixture. You also have 90% alcohol mixture. How much of the 90% mixture will you need to add to obtain the desired solution?

Solution

The problem on the screen asks you to solve a mixture problem involving alcohol solutions. Specifically, you are given:

  • 480 mL of a 5% alcohol solution.
  • A 90% alcohol mixture is also available.

You need to determine how much of the 90% alcohol mixture should be added to obtain a 10% alcohol solution.

Let’s define the variables:

  • Let xx be the amount (in mL) of the 90% alcohol solution to add.

Step-by-Step Solution:

  1. Alcohol in the 5% solution: The amount of pure alcohol in the 480 mL of the 5% solution is: 0.05×480=24 mL of alcohol.0.05 \times 480 = 24 \text{ mL of alcohol.}

  2. Alcohol in the 90% solution: The amount of pure alcohol in xx mL of the 90% solution is: 0.90×x=0.90x mL of alcohol.0.90 \times x = 0.90x \text{ mL of alcohol.}

  3. Final amount of alcohol in the mixture: After mixing, the total volume of the solution will be 480+x480 + x mL. The desired concentration is 10%, so the total amount of alcohol should be: 0.10×(480+x)=48+0.10x mL of alcohol.0.10 \times (480 + x) = 48 + 0.10x \text{ mL of alcohol.}

  4. Set up the equation: The amount of alcohol from both the 5% solution and the 90% solution should add up to the total amount of alcohol in the final solution: 24+0.90x=48+0.10x24 + 0.90x = 48 + 0.10x

  5. Solve for xx: Subtract 0.10x0.10x from both sides: 24+0.80x=4824 + 0.80x = 48 Subtract 24 from both sides: 0.80x=240.80x = 24 Divide both sides by 0.80: x=240.80=30 mL.x = \frac{24}{0.80} = 30 \text{ mL.}

Final Answer:

You need to add 30 mL of the 90% alcohol solution to obtain the desired mixture.

Would you like more details or have any questions about the steps? Here are 5 related questions to extend the learning:

  1. What if the original solution had a different concentration, say 7%? How would the equation change?
  2. How would the solution change if you needed to end with 15% alcohol instead of 10%?
  3. Can this problem be solved using a system of linear equations? How?
  4. How does the total volume affect the final alcohol concentration?
  5. What if the available alcohol concentrations were 50% and 90% instead of 5% and 90%?

Tip: Always ensure that the units (mL, percentage) are consistent throughout the calculations to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Mixture Problems
Systems of Linear Equations
Algebra

Formulas

Amount of alcohol in a solution = percentage × volume
Total alcohol = alcohol from first solution + alcohol from second solution

Theorems

Linear Equations

Suitable Grade Level

Grades 10-12