Math Problem Statement

Manakah pelarut terbaik dari ketiga gabungan tersebut?

Solution

To solve this problem, we aim to determine the best combination of solvents that results in the largest value of the density (ρcampuran\rho_{\text{campuran}}) for the mixtures described. Here's the step-by-step process:


Step 1: Understand the Formula

The formula for the density of the mixture is given by: ρcampuran=m1+m2+m3v1+v2+v3\rho_{\text{campuran}} = \frac{m_1 + m_2 + m_3}{v_1 + v_2 + v_3} Where:

  • m1,m2,m3m_1, m_2, m_3 are the masses of the three selected solvents.
  • v1,v2,v3v_1, v_2, v_3 are their corresponding volumes.

Step 2: Extract Information from the Table

From the table, we know:

LarutanMassa (g)Volume (mL)Density (ρ=mv\rho = \frac{m}{v})
A1001001.01.0 g/mL
B502000.250.25 g/mL
CXX300Unknown (XX)
D25500.50.5 g/mL
E2004000.50.5 g/mL

Step 3: Solve for XX (Mass of C)

We calculate XX using its density formula, assuming the density of CC is given as 0.250.25 g/mL: ρC=mCvC    0.25=X300    X=75g.\rho_C = \frac{m_C}{v_C} \implies 0.25 = \frac{X}{300} \implies X = 75 \, \text{g}.

Now the updated table is:

LarutanMassa (g)Volume (mL)Density (ρ=mv\rho = \frac{m}{v})
A1001001.01.0 g/mL
B502000.250.25 g/mL
C753000.250.25 g/mL
D25500.50.5 g/mL
E2004000.50.5 g/mL

Step 4: Calculate Densities of Combinations

For each combination (A to E), compute ρcampuran\rho_{\text{campuran}}:

  1. Option A (A + B + C): ρ=100+50+75100+200+300=225600=0.375g/mL.\rho = \frac{100 + 50 + 75}{100 + 200 + 300} = \frac{225}{600} = 0.375 \, \text{g/mL}.

  2. Option B (A + D + E): ρ=100+25+200100+50+400=3255500.591g/mL.\rho = \frac{100 + 25 + 200}{100 + 50 + 400} = \frac{325}{550} \approx 0.591 \, \text{g/mL}.

  3. Option C (B + C + E): ρ=50+75+200200+300+400=3259000.361g/mL.\rho = \frac{50 + 75 + 200}{200 + 300 + 400} = \frac{325}{900} \approx 0.361 \, \text{g/mL}.

  4. Option D (A + C + D): ρ=100+75+25100+300+50=2004500.444g/mL.\rho = \frac{100 + 75 + 25}{100 + 300 + 50} = \frac{200}{450} \approx 0.444 \, \text{g/mL}.

  5. Option E (B + C + D): ρ=50+75+25200+300+50=1505500.273g/mL.\rho = \frac{50 + 75 + 25}{200 + 300 + 50} = \frac{150}{550} \approx 0.273 \, \text{g/mL}.


Step 5: Compare the Results

The densities are:

  • A + B + C: 0.3750.375
  • A + D + E: 0.5910.591 (highest)
  • B + C + E: 0.3610.361
  • A + C + D: 0.4440.444
  • B + C + D: 0.2730.273

The best combination is (B) A + D + E.


Final Answer:

(B) A + D + E


Do you want further clarifications or details on the calculations? Here are 5 related questions to expand the topic:

  1. How does the order of combining solvents affect the density in real experiments?
  2. Can you calculate the density if one of the solvents had a varying temperature or concentration?
  3. What happens if the volume of one of the solvents changes slightly during mixing?
  4. How does density relate to other physical properties of the solution, such as viscosity?
  5. Could we use this approach to mix four or more solvents effectively?

Tip: When mixing solvents, always consider density and miscibility to ensure uniform solutions.

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Math Problem Analysis

Mathematical Concepts

Density
Mixtures
Mass and Volume

Formulas

Density formula: \( \rho = \frac{m}{v} \)
Mixture density formula: \( \rho_{\text{campuran}} = \frac{m_1 + m_2 + m_3}{v_1 + v_2 + v_3} \)

Theorems

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Suitable Grade Level

Grades 10-12