Math Problem Statement
Solution
We are given an open-top hollow cylinder, with a volume of , and we need to find the minimum surface area.
Formulae involved:
-
Volume of a cylinder: where:
- is the volume,
- is the radius,
- is the height.
-
Surface area of an open-top cylinder: where:
- The first term is the area of the base,
- The second term is the lateral surface area.
Step 1: Express height in terms of and
From the volume formula: Substitute :
Step 2: Substitute into the surface area formula
Simplify:
Step 3: Minimize the surface area
To minimize , we take the derivative of with respect to , set it to zero, and solve for .
Set : Multiply both sides by : Solve for :
Let me calculate the value of .The radius is approximately .
Step 4: Find the corresponding height
Using the formula , we can calculate the height. Let me compute that next.The height is also approximately .
Step 5: Calculate the minimum surface area
Now, let's calculate the surface area using the formula: Let me compute the minimum surface area.The minimum surface area of the open-top hollow cylinder is approximately .
Would you like further details or have any questions?
Here are 5 related questions you might consider:
- How does the surface area change with different cylinder heights?
- What would the surface area be if the cylinder had a closed top?
- How do you derive the optimal dimensions for a different volume?
- Can this method be applied to minimize the surface area of other shapes?
- How does the ratio between height and radius affect the efficiency of material usage?
Tip: When solving optimization problems involving geometry, always check if taking derivatives helps find minimum or maximum values efficiently.
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Math Problem Analysis
Mathematical Concepts
Optimization
Surface Area
Derivatives
Geometry
Formulas
Volume of cylinder: V = πr^2h
Surface area of open-top cylinder: A = πr^2 + 2πrh
Derivative to minimize surface area: dA/dr = 2πr - 324/r^2
Theorems
Optimization using derivatives
Surface area and volume relationships
Suitable Grade Level
Grades 10-12
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