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The problem asks to find the coordinates of the midpoint \( M \) of the segment \( ST \), and then find the length of the segment \( ST \).

### Given Points:
- \( S(6, -3) \)
- \( T(7, -2) \)

### Steps:

1. **Midpoint Formula**: The formula for the midpoint \( M \) of a segment connecting two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is:
   \[
   M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
   \]
   Applying this formula to points \( S(6, -3) \) and \( T(7, -2) \):
   \[
   M = \left( \frac{6 + 7}{2}, \frac{-3 + (-2)}{2} \right)
   \]
   \[
   M = \left( \frac{13}{2}, \frac{-5}{2} \right)
   \]
   \[
   M = (6.5, -2.5)
   \]

   Thus, the midpoint is \( M(6.5, -2.5) \), which matches the given result.

2. **Length of Segment**: The length of the segment \( ST \) can be found using the distance formula:
   \[
   d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
   \]
   For \( S(6, -3) \) and \( T(7, -2) \):
   \[
   d = \sqrt{(7 - 6)^2 + (-2 - (-3))^2}
   \]
   \[
   d = \sqrt{(1)^2 + (1)^2}
   \]
   \[
   d = \sqrt{1 + 1} = \sqrt{2} \approx 1.41
   \]
   
   The calculated length is approximately 1.41, which is very close to the provided length of \( 1.4 \).

### Summary:
- Midpoint \( M = (6.5, -2.5) \)
- Length of segment \( ST = 1.41 \)

Would you like more details on any step? 

Here are five related questions you could explore:
1. What happens if the points have more complex coordinates?
2. How would you find the midpoint in three-dimensional space?
3. Can the midpoint be used to divide a line segment in other ratios?
4. How do you calculate the length if the segment is vertical or horizontal?
5. How does the distance formula relate to the Pythagorean theorem?

**Tip**: Always verify your midpoint by ensuring the calculated coordinates lie exactly halfway between the given points.

The endpoints of segment ST are given: S(6, -3) and T(7, -2). Find the coordinates of the midpoint M and the length of segment ST.

This problem involves finding the midpoint and the length of segment ST between the given points S(6, -3) and T(7, -2) using the midpoint and distance formulas. Perfect for students in Grades 7-9 exploring coordinate geometry.

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