Math Problem Statement

평균: YY의 평균은 n⋅1−ppnp1−p​입니다.

분산: YY의 분산은 n⋅1−pp2np21−p​입니다.이걸 영어로해줘

Solution

Sure! Here's the translation:

Mean: The mean of YY is n1ppn \cdot \frac{1 - p}{p}.

Variance: The variance of YY is n1pp2n \cdot \frac{1 - p}{p^2}.

Let me know if you need further clarification or if you have any questions! Here are some related questions you might find useful:

  1. What is the relationship between mean and variance in this case?
  2. How do you calculate the standard deviation from variance?
  3. What is the definition of binomial distribution and how does it relate to this formula?
  4. Can you provide an example to illustrate this formula?
  5. What would happen to the mean and variance if pp approaches 0 or 1?

Tip: Always check if your formulas are based on a specific distribution (in this case, it seems like it might be related to a binomial distribution).

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Math Problem Analysis

Mathematical Concepts

Statistics
Mean
Variance
Probability Theory

Formulas

Mean of Y*Y* = n * (1 - p) / p
Variance of Y*Y* = n * (1 - p) / (p^2)

Theorems

Binomial Distribution (implied)

Suitable Grade Level

Grades 10-12