Math Problem Statement

Does the function graphed satisfy the hypotheses of the Mean Value Theorem on the interval [a, b]?

Solution

To determine whether the function satisfies the Mean Value Theorem (MVT) on the interval [a,b][a, b], let's analyze the graph and address the following key points:

Step 1: Check the Hypotheses of MVT

The Mean Value Theorem requires two conditions to be met on the interval [a,b][a, b]:

  1. The function must be continuous on the closed interval [a,b][a, b].
  2. The function must be differentiable on the open interval (a,b)(a, b).

From the graph, if the function is a continuous curve without any breaks or jumps on [a,b][a, b] and there are no sharp corners or cusps that indicate non-differentiability, then it would satisfy these hypotheses.

Step 2: Does the Graph Satisfy the Conclusion of MVT?

If the hypotheses are satisfied, then MVT states that there exists at least one point cc in the open interval (a,b)(a, b) such that: f(c)=f(b)f(a)baf'(c) = \frac{f(b) - f(a)}{b - a}

This means there is at least one point where the slope of the tangent line equals the slope of the secant line connecting f(a)f(a) and f(b)f(b). Based on the graph:

  • Identify f(a)f(a) and f(b)f(b), then calculate the slope f(b)f(a)ba\frac{f(b) - f(a)}{b - a}.
  • Look for where the tangent line’s slope equals this value.

Analysis of the Graph

From the graph, we observe the following:

  • There is a clear line segment between points aa and nn, and between nn and pp, suggesting the function is piecewise linear. The function is continuous.
  • Differentiability might be an issue at points nn and pp if there are sharp corners or changes in direction.

Given the function's piecewise linear nature, it appears to be differentiable except possibly at nn and pp. Therefore, the function likely does not satisfy the differentiability condition throughout (a,b)(a, b) if there are sharp points, so MVT might not apply.

Conclusion:

  1. Hypotheses: It might fail the differentiability requirement due to the sharp points at nn and pp. Thus, MVT may not apply.
  2. Conclusion: If MVT doesn't apply, we can't guarantee a point cc exists as per MVT. However, if it were differentiable, the slope f(c)f'(c) would match the secant line’s slope.

Would you like a more detailed breakdown, or do you have any specific questions?

Further Exploration:

  1. What are the exact coordinates of aa and bb to compute the secant line's slope?
  2. Are the points nn and pp sharp turns, or do they just appear that way?
  3. How can we determine if a function is differentiable at a specific point on a graph?
  4. What is the geometric interpretation of the Mean Value Theorem?
  5. Can a function be continuous but not differentiable, and how does that impact MVT?

Tip:

When applying the Mean Value Theorem, always double-check for continuity and differentiability across the specified interval. If there’s a sharp corner or discontinuity, MVT may not hold.

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Math Problem Analysis

Mathematical Concepts

Calculus
Continuity
Differentiability

Formulas

f'(c) = (f(b) - f(a)) / (b - a)

Theorems

Mean Value Theorem

Suitable Grade Level

Grades 11-12 or College Level