Math Problem Statement

On a test that has a normal distribution, a score of 77 falls two standard deviations above the mean, and a score of 61 falls two standard deviations below the mean. Determine the mean of this test.

Solution

To solve for the mean (μ\mu) of the test, let's analyze the problem systematically:

Step 1: Understanding the normal distribution

  • A score of 77 is two standard deviations above the mean, meaning: 77=μ+2σ77 = \mu + 2\sigma
  • A score of 61 is two standard deviations below the mean, meaning: 61=μ2σ61 = \mu - 2\sigma

Here, σ\sigma represents the standard deviation.


Step 2: Set up the equations

From the two equations above:

  1. 77=μ+2σ77 = \mu + 2\sigma
  2. 61=μ2σ61 = \mu - 2\sigma

Step 3: Eliminate σ\sigma

Add the two equations together to eliminate σ\sigma: (77)+(61)=(μ+2σ)+(μ2σ)(77) + (61) = (\mu + 2\sigma) + (\mu - 2\sigma) 138=2μ138 = 2\mu


Step 4: Solve for μ\mu

Divide both sides by 2: μ=1382=69\mu = \frac{138}{2} = 69


Final Answer:

The mean of the test is 69.


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Related Questions:

  1. How do you find the standard deviation (σ\sigma) using the same data?
  2. What are the properties of a normal distribution?
  3. How do z-scores relate to standard deviations in a normal distribution?
  4. Can you verify the solution by substituting μ\mu back into the equations?
  5. How do you calculate probabilities using a normal distribution?

Tip:

In a normal distribution, approximately 68% of the data falls within one standard deviation, 95% within two, and 99.7% within three!

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Math Problem Analysis

Mathematical Concepts

Normal Distribution
Algebra
Standard Deviation
Mean

Formulas

\( 77 = \mu + 2\sigma \)
\( 61 = \mu - 2\sigma \)
\( \mu = \frac{138}{2} = 69 \)

Theorems

Properties of Normal Distribution

Suitable Grade Level

Grades 9-11