Let’s solve the two questions based on the provided salaries.

The salaries of the 10 employees are:

• Brandon: $45,000
• Robert: $58,000
• Chloe: $62,000
• Andrew: $59,000
• David: $70,000
• Tanya: $84,000
• Rodney: $49,000
• Sally: $67,000
• Manuel: $78,000
• Alexis: $68,000

1. Mean Salary Calculation:

The mean (average) is found by summing all the salaries and dividing by the number of employees.

$\text{Mean} = \frac{45,000 + 58,000 + 62,000 + 59,000 + 70,000 + 84,000 + 49,000 + 67,000 + 78,000 + 68,000}{10}$

$\text{Sum} = 640,000$

$\text{Mean} = \frac{640,000}{10} = 64,000$

So, the mean salary is $64,000.

2. Median Salary Calculation:

To find the median, we first arrange the salaries in ascending order:

$45,000, 49,000, 58,000, 59,000, 62,000, 67,000, 68,000, 70,000, 78,000, 84,000$

Since there are 10 values (even number), the median will be the average of the 5th and 6th salaries.

$\text{Median} = \frac{62,000 + 67,000}{2} = \frac{129,000}{2} = 64,500$

So, the median salary is $64,500.

Answer Choices:

• Mean: $64,000
• Median: $64,500

Thus, the correct answer to select is:
"Mean: $64,000, Median: $64,500"

Do you need further clarifications?
Here are 5 related questions for practice:

1. What does the mean tell you about the data distribution?
2. What happens to the mean if the highest salary increases by $10,000?
3. Why is the median a better measure when there are outliers?
4. What is the range of the salaries in this list?
5. How would the mode be useful in this dataset?

Tip: Use the median when you want to minimize the effect of extreme values in the dataset.