A ball thrown into the air from a building 100 ft high travels along a path described by y = -1+1+100, where y is the height in feet and z is the horizontal distance from the building in feet. What is the maximum height the ball will reach?

The equation you provided is:

\[
y = -1 + 1 + 100
\]

This simplifies to:

\[
y = 100
\]

It appears that the equation doesn’t model the ball's parabolic trajectory properly. A typical equation for a ball's path is quadratic, like:

\[
y = -ax^2 + bx + c
\]

where \(y\) is the height, \(x\) is the horizontal distance, and the constants \(a\), \(b\), and \(c\) describe the motion.

If you meant to provide such a quadratic equation and simply made a typo, please clarify it. However, if the equation truly simplifies to just \(y = 100\), it means the ball remains at a constant height of 100 feet without rising or falling.

Let me know if you intended a different form of the equation!

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Learn how to find the maximum height of a ball thrown from a 100-foot building using quadratic equations and parabolic motion. This problem explores the vertex of a parabola, suitable for students in Grades 9-12.

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