Math Problem Statement

The lever BCD is hinged at C and attached to a control rod at B. Determine the maximum force P that can be safely applied at D if the maximum allowable value of the reaction at C is 250 lb.

Solution

To solve this problem, we need to determine the maximum force PP that can be safely applied at point DD such that the reaction at point CC does not exceed 250 lb.

Step-by-Step Solution:

  1. Understanding the Problem:

    • The lever BCDBCD is hinged at CC and connected to a control rod at BB.
    • The lever can pivot about point CC, and a force PP is applied at point DD.
    • We need to determine the maximum value of PP such that the reaction force at CC is limited to 250 lb.
  2. Free Body Diagram (FBD) and Forces:

    • At hinge CC, there will be a reaction force with both horizontal (CxC_x) and vertical (CyC_y) components.
    • Force PP is applied at DD in a horizontal direction.
    • The control rod at BB exerts a force, but since we are interested in finding the maximum PP, we focus on moments about point CC.
  3. Taking Moments about Point CC:

    • The moment arm for the force PP at DD is 7.5 in (vertical distance from CC to DD).
    • The moment arm for the force at BB is 3 in (vertical distance from CC to BB).

    The sum of moments about point CC is given by: MC=P×7.5FB×3=0M_C = P \times 7.5 - F_B \times 3 = 0

    Where FBF_B is the horizontal force in the control rod at BB.

    Solving for FBF_B, we have: FB=P×7.53=2.5PF_B = \frac{P \times 7.5}{3} = 2.5P

  4. Calculating the Reaction at Point CC:

    • The vertical reaction component Cy=0C_y = 0 since there are no vertical forces.
    • The horizontal reaction component CxC_x will balance both FBF_B and PP:

    Cx=FB+P=2.5P+P=3.5PC_x = F_B + P = 2.5P + P = 3.5P

    The resultant reaction force at CC is: RC=Cx=3.5PR_C = C_x = 3.5P

    Since the maximum allowable value for RCR_C is 250 lb: 3.5P=2503.5P = 250

    Solving for PP: P=2503.571.43 lbP = \frac{250}{3.5} \approx 71.43 \text{ lb}

Conclusion:

The maximum force PP that can be safely applied at DD is 71.43 lb.

Would you like more details on this problem or have any further questions?

Related Questions to Explore:

  1. How do you calculate moments in mechanics problems?
  2. What is the significance of the reaction forces at a hinge in a static problem?
  3. How do different forces affect the equilibrium of a system?
  4. How can you use trigonometry to solve mechanics problems involving angles?
  5. What are the conditions of equilibrium in two-dimensional force systems?

Tip:

When solving problems involving moments, always choose a point where the maximum number of unknown forces intersect to simplify the calculations.

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Math Problem Analysis

Mathematical Concepts

Statics
Equilibrium
Moments and Torque

Formulas

Moment about a point: M = F * d
Sum of moments: ∑M = 0
Sum of forces: ∑F = 0

Theorems

Conditions of static equilibrium: ∑F = 0 and ∑M = 0
Lever arm principle

Suitable Grade Level

Undergraduate Engineering